two unidentified flying discs are detected by a receiver, the angle of elevation from the receiver to each disc is 38.48 degrees
. The discs are hovering at a direct distance of 826metres and 1.296km from the receiver. Find the difference in height between the two flying discs.
1 answer:
Answer:
292.45 m
Step-by-step explanation:
Both disk are at an angle of 38.48°
From the image below we calculate as,
For disk B, direct distance is 1.296 km from receiver = 1296 m
Vertical height from ground will be = 1296 x sin38.48 = 806.42 m
For disk A, direct distance is 826 m from receiver
Verival height above ground = 826 x sin38.48 = 513.97 m
Difference in height between disks is 806.42 - 513.97 = 292.45 m
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Answer:
h(2)+g(2) = -3
Step-by-step explanation:
Replace the variable (t) with (
2) in the expression.
h (2) = 3 - 5
Replace the variable (t) with (
2) in the expression.
g(2) = 2(2) -5
Replace the function designators in h(2) +g(2) with the actual functions.
h(t) = 3 - 5 +2 (2) ← plug h(2) into 2(t)
Remove parentheses.
3 - 5 + 2(2)
Multiply 2 by 2
3 - 5 + 4 - 5
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Add -2 and 4
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Subtract 5 from 2
-3