We keep the 2x^2 because we can only subtract something from that if it also is squared. From there, we subtract the 7x from 2x^2-11. Since there is no previous x's in the 2x^2-11, we just make it -7x. So, without even continuing the problem, we see that A) is the correct answer because it is the only one with -7x.
Answer:
![{x}^{2} + 9x + 20](https://tex.z-dn.net/?f=%20%7Bx%7D%5E%7B2%7D%20%20%2B%209x%20%2B%2020)
Step-by-step explanation:
1) Use FOIL method: (a + b) (c + d) = ac + ad + bc + bd.
![{x}^{2} + 5x + 4x + 20](https://tex.z-dn.net/?f=%20%7Bx%7D%5E%7B2%7D%20%20%2B%205x%20%2B%204x%20%2B%2020)
2) Collect like terms.
![{x}^{2} + (5x + 4x) + 20](https://tex.z-dn.net/?f=%20%7Bx%7D%5E%7B2%7D%20%20%2B%20%285x%20%2B%204x%29%20%2B%2020)
3) Simplify.
![{x}^{2} + 9x + 20](https://tex.z-dn.net/?f=%20%7Bx%7D%5E%7B2%7D%20%20%2B%209x%20%2B%2020)
<em><u>Therefor</u></em><em><u>,</u></em><em><u> </u></em><em><u>the</u></em><em><u> </u></em><em><u>answer</u></em><em><u> </u></em><em><u>is</u></em><em><u> </u></em><u>x</u><u>²</u><u> </u><u>+</u><u> </u><u>9x</u><u> </u><u>+</u><u> </u><u>20</u>.
Answer:
a)219.8
b)3846.5
Step-by-step explanation:
a) circumference is pi*diameter, so 3.14*70 is 219.8
b) area is pir^2, and radius is 1/2 of diameter, it would be 3.14*35^2, so 3.14*1225, so 3,846.5 in^2.
The answer is to multiply
You got 21 papers on Monday. Because if you add 3 7 times it equals 21.
Hope it is correct!