Answer:
The amount of money separating the lowest 80% of the amount invested from the highest 20% in a sampling distribution of 10 of the family's real estate holdings is $238,281.57.
Step-by-step explanation:
Let the random variable <em>X</em> represent the amount of money that the family has invested in different real estate properties.
The random variable <em>X</em> follows a Normal distribution with parameters <em>μ</em> = $225,000 and <em>σ</em> = $50,000.
It is provided that the family has invested in <em>n</em> = 10 different real estate properties.
Then the mean and standard deviation of amount of money that the family has invested in these 10 different real estate properties is:

Now the lowest 80% of the amount invested can be represented as follows:

The value of <em>z</em> is 0.84.
*Use a <em>z</em>-table.
Compute the value of the mean amount invested as follows:


Thus, the amount of money separating the lowest 80% of the amount invested from the highest 20% in a sampling distribution of 10 of the family's real estate holdings is $238,281.57.
Answer:
there were 2 partners and 4 associates
Step-by-step explanation:
at 1300 per partner if you hire 2 thats 1300 x 2 = 2600
thrn 4 associates at 400 each 400 x 4 = 1600
now add 2600 + 1600 = 4200
Huh? Is their a picture or anything else that goes with that question?
Because the divider and dividend are actually smaller then factors