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salantis [7]
3 years ago
8

Choose the table that represents g(x) = −2⋅f(x) when f(x) = x + 4.

Mathematics
2 answers:
grigory [225]3 years ago
6 0

Answer: THIRD OPTION.

Step-by-step explanation:

Since  g(x) = -2f(x), then g(x) is:

g(x)=-2( x + 4)\\\\g(x)=-2x-8

In order to find which table represents g(x) = -2f(x) when f(x) = x + 4, you can follow these steps:

1. Substitute x=1 into the function g(x)=-2x-8:

 g(1)=-2(1)-8\\\\g(1)=-10

2. Substitute x=2 into the function g(x)=-2x-8:

 g(2)=-2(2)-8\\\\g(2)=-12

3. Substitute x=3 into the function g(x)=-2x-8:

 g(3)=-2(3)-8\\\\g(3)=-14

Notice that those ouput values (for x=1,\ x=2 and x=3) matches with the table provided in the third option. That table represents g(x) = -2f(x) when f(x) = x + 4:

Bogdan [553]3 years ago
5 0

Answer: C.                                                                                                             x g(x)

1 −10

2 −12

3 −14

Step-by-step explanation: i took the test babes

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Lim x-1 x³-2x²+3x-2/(2x^4-3x+1)
UkoKoshka [18]

Since the limit becomes the undetermined form

\displaystyle \lim_{x\to 1} \dfrac{x^3-2x^2+3x-2}{2x^4-3x+1} \to \dfrac{0}{0}

it means that both polynomials have a root at x=1. So, we can fact both numerator and denominator:

x^3-2x^2+3x-2 = (x-1)(x^2-x+2)

2x^4-3x+1 = (x-1)(2x^3+2x^2+2x-1)

So, the fraction becomes

\dfrac{(x-1)(x^2-x+2)}{(x-1)(2x^3+2x^2+2x-1)} = \dfrac{x^2-x+2}{2x^3+2x^2+2x-1}

Now, as x approaches 1, you have no problems anymore:

\displaystyle \lim_{x\to 1} \dfrac{x^2-x+2}{2x^3+2x^2+2x-1} \to \dfrac{2}{5}

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3 years ago
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julia-pushkina [17]
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3 years ago
. If her allowance had stayed the same, $9.00 a month, how many carnival tickets could she bu
jarptica [38.1K]

Answer:

a) number of tickets she could buy in a month with her allowance in 2008 = 4 tickets

b) number of tickets she could buy in a month with the same allowance in 2012 = 2 tickets

c) $5, an increase of 55.56%

d) $2, a 100% increase.

e) Hallie was able to buy more tickets in 2008 than in 2012.

f) $16

Step-by-step explanation:

The complete question is presented in the attached image to this answer.

a) Halie's allowance monthly = $9

Price of a ticket in 2008 = $2

number of tickets she could buy in a month with her allowance = (9/2) = 4.5 = 4 tickets (since there are no half tickets)

b) Halie's allowance monthly = $9

Price of a ticket in 2012 = $4

number of tickets she could buy in a month with her allowance = (9/4) = 2.25 = 2 tickets (since there are no quarter tickets)

c) In 2012, Hallie's allowance was $14.00 per month. How much did her monthly allowance increase between 2008 and 2012?

Her monthly allowance in 2008 = $9

Her monthly allowance in 2012 = $14

The increase = new allowance - old allowance = 14 - 9 = $5

In percentage terms,

% increase = 100% × (new - old)/(old)

% increase = 100% × (14 - 9)/9 = 55.56%

d) How much more did a carnival ticket cost in 2012 than it did in 2008?

Price of a ticket on 2008 = $2

Price of a ticket in 2012 = $4

Increase in price = 4 - 2 = $2

% increase = 100% × (4 - 2)/2 = 100%

e) Was Hallie able to buy more carnival tickets in 2008 or in 2012 with one month's allowance?

Hallie was able to buy more tickets in 2008 than in 2012.

f) What would Hallie's allowance need to be in 2012 in order for her to be able to buy as many carnival tickets as she could in 2008?

Hallie could buy 4 tickets in 2008.

Price of a ticket in 2012 = $4.

Price of 4 tickets in 2012 = 4 × $4 = $16

Hope this Helps!!!!

3 0
2 years ago
Can some one solve this
Roman55 [17]
Well, first you have to convert to one unit... then simplify
D:H
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150m:160m
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3 years ago
What is the mode of the following numbers?<br> 9,10,6,5,6
Llana [10]

Answer:

6

Step-by-step explanation:

The mode is the number which appears most often in a set of numbers in this case that would be 6 because it appears twice

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