Answer:
x < -4
General Formulas and Concepts:
<u>Pre-Algebra</u>
Step-by-step explanation:
<u>Step 1: Define inequality</u>
-16x - 10 > 14 - 10x
<u>Step 2: Solve for </u><em><u>x</u></em>
- Add 16x to both sides: -10 > 14 + 6x
- Subtract 14 on both sides: -24 > 6x
- Divide 6 on both sides: -4 > x
- Rewrite: x < -4
Here we see that any value <em>x</em> that is less than -4 would work as a solution.
Answer:
x =1
Step-by-step explanation:
Assuming the figures are similar, we can use ratios to solve
x 2
---- = -----
4 8
Using cross products
8x = 2*4
8x = 8
Divide by 8
8x/8 = 8/8
x=1
Salutations!
![5a-10b = 45](https://tex.z-dn.net/?f=5a-10b%20%3D%2045)
value of
![b = 3](https://tex.z-dn.net/?f=b%20%3D%203)
Multiply 10 and 3
![10*3=30](https://tex.z-dn.net/?f=10%2A3%3D30)
Now, you can solve the equation --
![5a-30=45](https://tex.z-dn.net/?f=5a-30%3D45)
separate the variables aside, and the numbers aside.
![5a=45 +30](https://tex.z-dn.net/?f=5a%3D45%20%2B30)
![5a=75](https://tex.z-dn.net/?f=5a%3D75)
![a=75/5](https://tex.z-dn.net/?f=a%3D75%2F5)
![a=15](https://tex.z-dn.net/?f=a%3D15)
Hope I helped (:
Have a great day!
Given:
The function is
![f(x)=\dfrac{4x}{x^2-16}](https://tex.z-dn.net/?f=f%28x%29%3D%5Cdfrac%7B4x%7D%7Bx%5E2-16%7D)
To find:
The asymptotes and zero of the function.
Solution:
We have,
![f(x)=\dfrac{4x}{x^2-16}](https://tex.z-dn.net/?f=f%28x%29%3D%5Cdfrac%7B4x%7D%7Bx%5E2-16%7D)
For zeroes, f(x)=0.
![\dfrac{4x}{x^2-16}=0](https://tex.z-dn.net/?f=%5Cdfrac%7B4x%7D%7Bx%5E2-16%7D%3D0)
![4x=0](https://tex.z-dn.net/?f=4x%3D0)
![x=0](https://tex.z-dn.net/?f=x%3D0)
Therefore, zero of the function is 0.
For vertical asymptote equate the denominator of the function equal to 0.
![x^2-16=0](https://tex.z-dn.net/?f=x%5E2-16%3D0)
![x^2=16](https://tex.z-dn.net/?f=x%5E2%3D16)
Taking square root on both sides, we get
![x=\pm \sqrt{16}](https://tex.z-dn.net/?f=x%3D%5Cpm%20%5Csqrt%7B16%7D)
![x=\pm 4](https://tex.z-dn.net/?f=x%3D%5Cpm%204)
So, vertical asymptotes are x=-4 and x=4.
Since degree of denominator is greater than degree of numerator, therefore, the horizontal asymptote is y=0.
Answer:
If 8 Treasure Chests per 4 Hours so
12 Treasure Chests for 6 Hours
10 treasure Chests for 5 Hours
Step-by-step explanation:
If 8 Chests every 4 Hours, then 2 Chests is every 1 hour. Count up each hour, add 2 chests.