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nikklg [1K]
3 years ago
6

What is the area, in square units, of the parallelogram shown below?

Mathematics
1 answer:
Anna11 [10]3 years ago
6 0
60? im not got with area for some strange reason
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Hello ! 
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Lunna [17]

<u>Step-by-step explanation</u> and Answers:

(\frac{1}{\sqrt{10}},\frac{3}{\sqrt{10}}) is in the format (cos, sin). So, adjacent = 1, opposite = 3, hypotenuse = \sqrt{10}

sin = \frac{opposite}{hypotenuse} = \frac{3}{\sqrt{10}}(\frac{\sqrt{10}}{\sqrt{10}}) = \frac{3\sqrt{10}}{10}

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sec = \frac{hypotenuse}{adjacent} = \frac{\sqrt{10}}{1} = \sqrt{10}

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