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nikklg [1K]
3 years ago
6

What is the area, in square units, of the parallelogram shown below?

Mathematics
1 answer:
Anna11 [10]3 years ago
6 0
60? im not got with area for some strange reason
You might be interested in
Which function is a quadratic function? y – 3x2 = 3(x2 + 5) + 1 y2 – 7x = 2(x2 + 6) + 7 y – 2x2 = 6(x3 + 5) – 4 y – 5x = 4(x + 5
Anna71 [15]

Answer:

Option A.

Step-by-step explanation:

The general form of a quadratic function is  

y=ax^2+bx+c

It means, power of y should be 1 and highest power of x should be 2.

In option A,

y-3x^2=3(x^2+5)+1

y-3x^2=3x^2+15+1

y=3x^2+16+3x^2

y=6x^2+16

It is a quadratic function.

In option B,

y^2-7x=2(x^2+6)+7

Here, power of y is 2. So, it is not be a quadratic function.

In option C,

y-2x^2=6(x^3+5)

Here, highest power of x is 3. So, it is not be a quadratic function.

In option D,

y-5x=4(x+5)+9

Here, highest power of x is 1. So, it is not be a quadratic function.

Therefore, the correct option is A.

7 0
3 years ago
What is the largest sum your can get when you add 2 3 digit numbers
Ksju [112]
The biggest 3 digits whole number is 999.

Hence, the biggest sum one can do with two of those is 999+999=1998
8 0
3 years ago
Read 2 more answers
Does 23^-1 (mod 1000) exist? If yes solve it.
sweet [91]

Yes, 23 has an inverse mod 1000 because gcd(23, 1000) = 1 (i.e. they are coprime).

Let <em>x</em> be the inverse. Then <em>x</em> is such that

23<em>x</em> ≡ 1 (mod 1000)

Use the Euclidean algorithm to solve for <em>x</em> :

1000 = 43×23 + 11

23 = 2×11 + 1

→   1 ≡ 23 - 2×11   (mod 1000)

→   1 ≡ 23 - 2×(1000 - 43×23)   (mod 1000)

→   1 ≡ 23 - 2×1000 + 86×23   (mod 1000)

→   1 ≡ 87×23 - 2×1000 ≡ 87×23   (mod 1000)

→   23⁻¹ ≡ 87   (mod 1000)

3 0
3 years ago
The null space for the matrix is spanned by the vector:_______
mafiozo [28]

Answer:

True

Step-by-step explanation:

The null space of matrix is set of all solutions to matrix. The linearly independent vectors forms subset which are spanned and forms the null space. The null space of vector can be found by reducing its echelon. The non zero rows formed are the null spaces of matrix.

8 0
3 years ago
Please help I'm really stuck
Anit [1.1K]
First factor the numerator
b^2-6b+8/b-4  * b+8/b-2

u will get
(b-2)(b-4)/(b-4)*(b-2)*b+8
those will cancel out each other will left only
b+8<span />
7 0
3 years ago
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