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Umnica [9.8K]
2 years ago
14

A learner finds a deck of 52 cards and then takes one card from the deck. What is the probability that the card is a king? Write

your answer as a decimal (correct to 2 decimal places).​
Mathematics
1 answer:
iVinArrow [24]2 years ago
7 0

Answer:

The odds of choosing a club from a full deck is 13/52, or 1/4. Since there are now only 51 cards and 12 clubs, the odds are 12/51, or .2352

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Find the equation of the line in slope-intercept form. e through (−5, 6) with slope = 3
love history [14]

Answer:

Step-by-step explanation:

y - 6 = 3(x + 5)

y - 6 = 3x + 15

y = 3x + 21

5 0
3 years ago
The line AB has the midpoint of (2,5) A has coordinates (1,7) find the coordinates of B
Pavel [41]

Answer:

Point B is at (3,3)

Step-by-step explanation:

the mid point is (2,5) and A is at (1,7)

first find the slope:

y1 - y2/x1 - x2

7 - 5/1 - 2

2/-1

-2/1

then go down 2 units and right 1 unit from (2,5):

(2 + 1, 5 - 2) => (3,3)

6 0
3 years ago
Which expressions are equivalent to the one below? Check all that apply.
Aleksandr [31]

Answer:

D

Step-by-step explanation:

(5·5)*x = 25*x =25^x

the rest are wrong

5 0
3 years ago
What does it mean when no metric prefix is used on a measurement
dolphi86 [110]

Answer: The measurement is not multiplied by a power of 10

i hope this helped <3

5 0
3 years ago
Match each of the trigonometric expressions below with the equivalent non-trigonometric function from the following list. Enter
Levart [38]

Answer:

Match each of the trigonometric expressions below with theequivalent non-trigonometric function from the following list.Enter the appropiate letter(A,B, C, D or E)in each blank

A . tan(arcsin(x/8))

B . cos (arsin (x/8))

C. (1/2)sin (2arcsin (x/8))

D . sin ( arctan (x/8))

E. cos (arctan (x/8))

These are the spaces to fill out :

.. ..........x/64 (sqrt(64-x^2))

.............x/sqrt(64+x^2)

.............sqrt(64-x^2)/8

..............x/sqrt(64-x^2)

..............8/sqrt(64+x^2)

A. ........tan(arcsin(x/8))  =......x/sqrt(64-x^2)

B .      cos (arsin (x/8))  ....sqrt(64-x^2)/8

Step-by-step explanation:

To solve this we have to find the missing sides to each of the triange discribed in prenthesis thus

A we have the sides of the triangle given by x, 8 and  \sqrt{8^{2} - x^{2} }or  \sqrt{64 - x^{2} }

thus tan(arcsin(x/8))  = \frac{x}{\sqrt{64 - x^{2} }}  =

Therefore  ........tan(arcsin(x/8))  =......x/sqrt(64-x^2)

B

Here we have cos = adjacent/hypotenuse where adjacent side is \sqrt{64 - x^{2} } and hypothenuse = 8 we have \sqrt{64 - x^{2} }/8

B .      cos (arsin (x/8))  ....sqrt(64-x^2)/8

4 0
3 years ago
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