We have that the electric field at the center of the metal ball due only to the charges on the surface of the metal ball is
From the question we are told that
A solid metal ball of radius 1.5 cm
bearing a charge of -15 nC is located near a hollow plastic ball of radius 1.9 cm bearing
uniformly distributed charge of -7 nC
The distance between the centers of the balls is 9 cm
Generally the equation for the electric field is mathematically given as
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Answer:
11 m/s
Explanation:
Impulse equals change in momentum.
I = Δ(mv)
Since mass isn't changing:
I = m Δv
16 Ns = (2.0 kg) (v - 3.0 m/s)
v = 11 m/s
Power = (energy) / (time)
= (1370 joules) / (100 seconds)
= 13.7 joules/second
= 13.7 watts .
That's not an awful lot of power, especially for a strenuous activity like
rock-climbing. Shoot ! Even I could probably perform at that level.
Compare 13.7 watts to the light power coming out of a 20-watt night light.
13.7 watts = 0.018 horsepower. (rounded)
Answer:
4 seconds
Explanation:
Given:
v₀ = 12 m/s
v = 32 m/s
a = 5 m/s²
Find: t
v = at + v₀
32 m/s = (5 m/s²) t + 12 m/s
t = 4 s