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Andreyy89
3 years ago
11

1. Water boils at 100°C at sea level. If the water in this experiment did not boil at 100°C, what could be the reason?

Physics
2 answers:
umka2103 [35]3 years ago
8 0

Answer:

It may not be at the sea level

Explanation:

The reason here is water only boils at sea level. This means that if you move water to a different height, say top of a mountain, the boiling temperature of water would change. This is due to the pressure drop at high place. The drop of pressure would make it harder to transform water liquid to gas, thus requiring more temperature.

yulyashka [42]3 years ago
8 0

Answer:

The experiment is not performed at sea level.

Or

And also there may be presence of impurities in the water used for the experiment

Explanation:

The boiling point of pure water at sea level is 100°C, but the boiling point can be affected mainly by two factors;

i) Pressure

ii) impurities

At higher altitudes ( above sea level) the atmospheric pressure is reduced (the higher you go the lower the atmospheric pressure), thereby leading to reduced boiling point of water (at lower pressure water boils faster). While if the altitude is lower than sea level atmospheric pressure is higher so water boils at higher temperatures (above 100°C).

Secondly, presence of impurities(e.g salt) in water increases the boiling point of water in most cases.

Therefore, if water does not boil at 100°C it may be as a result of the elevation (altitude) or the water may contain impurities.

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3 years ago
Falling raindrops frequently develop electric charges. Does this create noticeable forces between the droplets? Suppose two 1.8
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Answer:

a) F=2.048\times 10^{-7}\ N

b) a=0.1138\ m.s^{-2}

Explanation:

Given:

  • mass of raindrops, m=1.8\times 10^{-6}\ kg
  • charge on the raindrops, q=+21\times 10^{-12}\ C
  • horizontal distance between the raindrops, r=0.0044\ m

A)

<u>From the Coulomb's Law the force between the charges is given as:</u>

F=\frac{1}{4\pi.\epsilon_0} .\frac{q_1.q_2}{r^2}

we have:

\epsilon_0=8.854\times 10^{-12}\ C^2.N^{-1}.m^{-2}

<em>Now force:</em>

F=\frac{1}{4\pi\times 8.854\times 10^{-12}} .\frac{21\times 10^{-12}\times 21\times 10^{-12}}{0.0044^2}

F=2.048\times 10^{-7}\ N

B)

<u>Now the acceleration on the raindrops due to the electrostatic force:</u>

a=\frac{F}{m}

a=\frac{2.048\times 10^{-7}}{1.8\times 10^{-6}}

a=0.1138\ m.s^{-2}

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Part B
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<h3>Average daily power consumption</h3>

The average daily power consumption is the amount of electric energy consumed by an individual on a daily rate.

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<h3>Converting watts to kilowatts</h3>

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Thus, the number of kilowatts used by an individual to operate his appliances is determined as 12.1 kWh.

Learn  more about power here: brainly.com/question/13881533

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