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3 years ago

A barrel of oil contains roughly 6.1x109 J. How many kW-hr is this? Answer in units of kW-hr

Physics

1 answer:

PtichkaEL [24]3 years ago

6 0

Answer:

$1.694*10^3KW/hr$

Explanation:

Formula:

$KW/hr=E_{(change)}$

$P=\frac{E}{t}$

$(KW)(s)=1000J$

$(3600)(KW)(s)=3600*1000J$

$KW=3.6*10^6$

$\frac{6.1*10^9}{3.6*10^6}=\frac{x}{1KW}$

$1.694*10^3KW/hr$

Hope it helps

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