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Basile [38]
1 year ago
3

What does De identifying data with a code mean quizlet?

Mathematics
1 answer:
scoray [572]1 year ago
5 0

<u>De identifying data with a code -</u>

  • De-identifying data with a code refers to: Presenting data with a code that can be matched to other data.
  • Using a code to de-identify data allows researchers to match the data to other data with the same code, without disclosing the individual's PII.

What is de-identified data means?

  • Data de-identification is a form of dynamic data masking that refers to breaking the link between data and the individual with whom the data is initially associated.
  • Essentially, this requires removing or transforming personal identifiers

What is student administrative data?

  • For example, administrative data is the number of students enrolled in a school, libraries in a county, or fishing licenses in a state.
  • Typically, the institution collecting this information is either a government entity or a nonprofit organization.

Learn more about De identifying data

brainly.com/question/14843166

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What’s the answer, help please !
Stels [109]
4(5x - 2) - 2(9 - 3x)

= 26x - 26



8 0
3 years ago
Solve the given initial-value problem. (x + y)2 dx + (2xy + x2 − 2) dy = 0, y(1) = 1
Yuri [45]
Let's check if the ODE is exact. To do that, we want to show that if

\underbrace{(x+y)^2}_M\,\mathrm dx+\underbrace{(2xy+x^2-2)}_N\,\mathrm dy=0

then M_y=N_x. We have

M_y=2(x+y)
N_x=2y+2x=2(x+y)

so the equation is indeed exact. We're looking for a solution of the form \Psi(x,y)=C. Computing the total differential yields the original ODE,

\mathrm d\Psi=\Psi_x\,\mathrm dx+\Psi_y\,\mathrm dy=0
\implies\begin{cases}\Psi_x=(x+y)^2\\\Psi_y=2xy+x^2-2\end{cases}

Integrate both sides of the first PDE with respect to x; then

\displaystyle\int\Psi_x\,\mathrm dx=\int(x+y)^2\,\mathrm dx\implies\Psi(x,y)=\dfrac{(x+y)^3}3+f(y)

where f(y) is a function of y alone. Differentiate this with respect to y so that

\Psi_y=2xy+x^2-2=(x+y)^2+f'(y)
\implies2xy+x^2-2=x^2+2xy+y^2+f'(y)
f'(y)=-2-y^2\implies f(y)=-2y-\dfrac{y^3}3+C

So the solution to this ODE is

\Psi(x,y)=\dfrac{(x+y)^3}3-2y-\dfrac{y^3}3+C=C

i.e.


\dfrac{(x+y)^3}3-2y-\dfrac{y^3}3=C
6 0
3 years ago
Please solve with explanation
Eva8 [605]

Answer:

Add

Step-by-step explanation:

Add subtract multiply

5 0
3 years ago
Help? Due today please
kiruha [24]

Answer:

PR

Step-by-step explanation:

They're congruent, so corresponding sides of corresponding congruent figures are congruent. A corresponds to P and C corresponds to R, so AC is congruent to PR

6 0
4 years ago
Select the two expression equivalent to the given expression. Let x,y and z by numbers​
Lesechka [4]

Answer:

ponits

Step-by-step explanation:

5 0
3 years ago
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