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svetoff [14.1K]

3 years ago

15

Is Angel 1: 60 and angle 2: 30 a complementary angle

2 answers:

Fed [463]3 years ago

7 0

Answer:

Yes

Step-by-step explanation:

They add up to 90 degrees.

PtichkaEL [24]3 years ago

4 0

Yes, Two Angles are Complementary when they add up to 90 degrees (a Right Angle). They don't have to be next to each other, just so long as the total is 90 degrees.

You might be interested in

Would you say that pythagoras’ theorem holds true for hexagons as well? why or why not

kifflom [539]

No, the Pythgorean Theorem only applies to right triangles. To get two right triangles, you divide a rectangle diagonally. Dividing a hexagon into two pieces produces trapezoids or pentagons depending where it is divided.

7 0

3 years ago

A part of Jennifer’s work is to solve the equation 2(6x^2-3)=11x^2-x is shown below

kotykmax [81]

Answer:

Step-by-step explanation:

2(6x² - 3) = 11x² - x

2*6x² - 2*3 = 11x² - x

12x² - 6 = 11x² -x

Subtract 11x² from both sides

12x² - 11x² - 6 = -x

x² - 6 = -x

x² + x - 6= 0

Sum =1

Product = -6

Factors = 3 , (-2) { 3*(-2) = -6 & 3 +(-2) = 1}

x² + 3x - 2x - 6 = 0

x(x + 3) - 2(x + 3)= 0

(x +3)(x - 2) = 0

7 0

3 years ago

Help!! 50 points and brainliest!

Viktor [21]

Answer:

Second choice:

$x=2t$

$y=4t^2+4t-3$

Fifth choice:

$x=t+1$

$y=t^2+4t$

Step-by-step explanation:

Let's look at choice 1.

$x=t+1$

$y=t^2+2t$

I'm going to subtract 1 on both sides for the first equation giving me $x-1=t$ . I will replace the $t$ in the second equation with this substitution from equation 1.

$y=(x-1)^2+2(x-1)$

Expand using the distributive property and the identity $(u+v)^2=u^2+2uv+v^2$ :

$y=(x^2-2x+1)+(2x-2)$

$y=x^2+(-2x+2x)+(1-2)$

$y=x^2+0+-1$

$y=x^2$

So this not the desired result.

Let's look at choice 2.

$x=2t$

$y=4t^2+4t-3$

Solve the first equation for $t$ by dividing both sides by 2:

$t=\frac{x}{2}$ .

Let's plug this into equation 2:

$y=4(\frac{x}{2})^2+4(\frac{x}{2})-3$

$y=4(\frac{x^2}{4})+2x-3$

$y=x^2+2x-3$

This is the desired result.

Choice 3:

$x=t-3$

$y=t^2+2t$

Solve the first equation for $t$ by adding 3 on both sides:

$x+3=t$ .

Plug into second equation:

$y=(x+3)^2+2(x+3)$

Expanding using the distributive property and the earlier identity mentioned to expand the binomial square:

$y=(x^2+6x+9)+(2x+6)$

$y=(x^2)+(6x+2x)+(9+6)$

$y=x^2+8x+15$

Not the desired result.

Choice 4:

$x=t^2$

$y=2t-3$

I'm going to solve the bottom equation for $t$ since I don't want to deal with square roots.

Add 3 on both sides:

$y+3=2t$

Divide both sides by 2:

$\frac{y+3}{2}=t$

Plug into equation 1:

$x=(\frac{y+3}{2})^2$

This is not the desired result because the $y$ variable will be squared now instead of the $x$ variable.

Choice 5:

$x=t+1$

$y=t^2+4t$

Solve the first equation for $t$ by subtracting 1 on both sides:

$x-1=t$ .

Plug into equation 2:

$y=(x-1)^2+4(x-1)$

Distribute and use the binomial square identity used earlier:

$y=(x^2-2x+1)+(4x-4)$

$y=(x^2)+(-2x+4x)+(1-4)$

$y=x^2+2x+-3$

$y=x^2+2x-3$ .

This is the desired result.

3 0

3 years ago

Read 2 more answers

3. You need to hire a taxi. Taxi A charges $9.25 plus $1.50 per mile. Taxi B charges $10.50 plus $1.25 per mile. Find the number

lapo4ka [179]

Answer:

five miles

Step-by-step explanation:

taxi A: for one mile: 10.75

taxi B: for one mile: 11.75

two miles: A: 12.25 B: 13

three miles: A: 13.75 B: 14.25

four miles: A: 15.25 B: 15.5

five miles: A: 16.75 B: 16.75

5 0

2 years ago

Which function is the inverse of f(x) = 2x + 3 ?<br> Help

bearhunter [10]

Answer:

The inverse is 1/2x -3/2

Step-by-step explanation:

y =2x+3

Exchange x and y

x = 2y+3

Solve for y, subtracting 3 from each side

x-3 = 2y+3-3

x-3 =2y

Divide each side by 2

(x-3)/2 = 2y/2

1/2x - 3/2 =y

The inverse is 1/2x -3/2

7 0

3 years ago

Read 2 more answers