Can anyone answer this for me?

Which of the following graphs represents the solution set for y less than -2x -4

Alona [7]

Where's the graphs ?????

6 0

3 years ago

Point B is a point of tangency. Find the radius r of OC.

Bumek [7]

Answer:

r = 16 units

Step-by-step explanation:

From the figure attached,

AB is the tangent drawn from a point A to the circle C.

BC = r [Radius of the circle]

Length of AC = (18 + r)

AB = 30

By the property of a tangent drawn to a circle,

"Radius of a circle and tangent are perpendicular to each other"

AB ⊥ BC

By applying Pythagoras theorem in ΔABC,

AB² + BC² = AC²

(30)² + r² = (r + 18)²

900 + r² = r² + 36r + 324

36r = 900 - 324

r = $\frac{576}{36}$

r = 16 units

6 0

2 years ago

Please, I need help in this ??

nignag [31]

Answer:

$\int\frac{x^{4}}{x^{4} -1}dx = x + \frac{1}{4} ln(x-1) - \frac{1}{4} ln(x+1)-\frac{1}{2} arctanx + c$

Step-by-step explanation:

$\int\frac{x^{4}}{x^{4} -1}dx$

Adding and Subtracting 1 to the Numerator

$\int\frac{x^{4} - 1 + 1}{x^{4} -1}dx$

Dividing Numerator seperately by $x^{4} - 1$

$\int 1 + \frac{1}{x^{4}-1 }\, dx$

Here integral of 1 is x +c1 (where c1 is constant of integration

$x + c1 + \int\frac{1}{(x-1)(x+1)(x^{2}+1)}\, dx$ ----------------------------------(1)

We apply method of partial fractions to perform the integral

$\frac{1}{(x-1)(x+1)(x^{2}+1)}$ = $\frac{A}{x-1} + \frac{B}{x+1} + \frac{C}{x^{2} + 1}$ ------------------------------------------(2)

$\frac{1}{(x-1)(x+1)(x^{2}+1)} = \frac{A(x+1)(x^{2} +1) + B(x-1)(x^{2} +1) + C(x-1)(x+1)}{(x-1)(x+1)(x^{2} +1)}$

1 = $A(x+1)(x^{2} +1) + B(x-1)(x^{2} +1) + C(x-1)(x+1)$ -------------------------(3)

Substitute x= 1 , -1 , i in equation (3)

1 = A(1+1)(1+1)

A = $\frac{1}{4}$

1 = B(-1-1)(1+1)

B = $-\frac{1}{4}$

1 = C(i-1)(i+1)

C = $-\frac{1}{2}$

Substituting A, B, C in equation (2)

$\int\frac{x^{4}}{x^{4} -1}dx$ = $\int\frac{1}{4(x-1)} - \frac{1}{4(x+1)} -\frac{1}{2(x^{2}+1) }$

On integration

Here $\int \frac{1}{x}dx = lnx and \int\frac{1}{x^{2}+1 } dx = arctanx$

$\int\frac{x^{4}}{x^{4} -1}dx$ = $\frac{1}{4} ln(x-1)$ - $\frac{1}{4} ln(x+1)$ - $\frac{1}{2} arctanx$ + c2---------------------------------------(4)

Substitute equation (4) back in equation (1) we get

$x + c1 + \frac{1}{4} ln(x-1) - \frac{1}{4} ln(x+1) - \frac{1}{2} arctanx + c2$

Here c1 + c2 can be added to another and written as c

Therefore,

$\int\frac{x^{4}}{x^{4} -1}dx = x + \frac{1}{4} ln(x-1) - \frac{1}{4} ln(x+1)-\frac{1}{2} arctanx + c$

4 0

3 years ago

A partir del término general, calcular los 4 primerostérminos. (Considere que debe asignar

Scorpion4ik [409]

Answer:

$4,7,12,19,...$

Step-by-step explanation:

<u><em>The question in English is:</em></u>

From the general term, calculate the first 4 terms.

(Consider that you must assign values to the variable n)

we have

$b_n=n^2+3$

step 1

Calculate the first term

For n=1

$b_1=(1)^2+3=4$

step 2

Calculate the second term

For n=2

$b_2=(2)^2+3=7$

step 3

Calculate the third term

For n=3

$b_3=(3)^2+3=12$

step 4

Calculate the fourth term

For n=4

$b_4=(4)^2+3=19$

therefore

the first 4 terms are

$4,7,12,19,...$

4 0

3 years ago

A grounds crew is marking out a circular logo at the center of a football field. The logo will

patriot [66]

Answer:

circumference of a circle formula is C=2*pi*r

Step-by-step explanation:

then

141.3 = 2*pi * r

solve for r

141.3/ (2*pi) = r

22.48859 feet

diameter is 2*r

2*22.48859= 44.9771 feet

divide by 3 because there are 3 feet in one yard

44.9771/3= 14.99239 yds.

it doesn't say to round off, but I would call this 15 yds.

Diameter is 15 yards ± .008 yds That's just about 1/4 of an inch

8 0

2 years ago