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1 year ago

Write equations to show whether the solubility of either of the following is affected by pH: (b) CuS.

Chemistry

1 answer:

hram777 [196]1 year ago

7 0

There will be increase in solubility.

What means solubility in water?

Water solubility is a measure of the amount of chemical substance that can dissolve in water at a specific temperature.
The unit of solubility is generally in mg/L (milligrams per liter) or ppm (parts per million).
Sugar cubes added to a cup of tea or coffee are a common example of a solution.
The property which helps sugar molecules to dissolve is known as solubility.
Hence, the term solubility can be defined as a property of a substance (solute) to dissolve in a given solvent.

In case of CuS, S²⁻ will combine with [H⁺] ions to form a precipitate of H₂S .

Hence, there will be increase in solubility.

Learn more about solubility

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How many atoms are in 3.75 moles of Carbon?

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Answer:

One mole of Carbon contains 6.022x10^23 atoms.

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One mole of every element or compound is equal to 6.022x10^23 number of Atoms or Molecules and this number of atoms is known as Avogadro's Number.

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3 years ago

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3 years ago

10.0 g Cu, C Cu = 0.385 J/g°C 10.0 g Al, C Al = 0.903 J/g°C 10.0 g ethanol, Methanol = 2.42 J/g°C 10.0 g H2O, CH2O = 4.18 J/g°C

Mazyrski [523]

Answer:

Lead shows the greatest temperature change upon absorbing 100.0 J of heat.

Explanation:

$Q=mc\Delte T$

Q = Energy gained or lost by the substance

m = mass of the substance

c = specific heat of the substance

ΔT = change in temperature

1) 10.0 g of copper

Q = 100.0 J (positive means that heat is gained)

m = 10.0 g

Specific heat of the copper = c = 0.385 J/g°C

$\Delta T=\frac{Q}{mc}$

$=\frac{100.0 J}{10 g\times 0.385J/g^oC}=25.97^oC$

2) 10.0 g of aluminium

Q = 100.0 J (positive means that heat is gained)

m = 10.0 g

Specific heat of the aluminium= c = 0.903 J/g°C

$\Delta T=\frac{Q}{mc}$

$=\frac{100.0 J}{10 g\times 0.903 J/g^oC}=11.07^oC$

3) 10.0 g of ethanol

Q = 100.0 J (positive means that heat is gained)

m = 10.0 g

Specific heat of the ethanol= c = 2.42 J/g°C

$\Delta T=\frac{Q}{mc}$

$=\frac{100.0 J}{10 g\times 2.42 J/g^oC}=4.13 ^oC$

4) 10.0 g of water

Q = 100.0 J (positive means that heat is gained)

m = 10.0 g

Specific heat of the water = c = 4.18J/g°C

$\Delta T=\frac{Q}{mc}$

$=\frac{100.0 J}{10 g\times 4.18 J/g^oC}=2.39 ^oC$

5) 10.0 g of lead

Q = 100.0 J (positive means that heat is gained)

m = 10.0 g

Specific heat of the lead= c = 0.128 J/g°C

$\Delta T=\frac{Q}{mc}$

$=\frac{100.0 J}{10 g\times 0.128 J/g^oC}=78.125^oC$

Lead shows the greatest temperature change upon absorbing 100.0 J of heat.

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4 years ago

How many significant figures does 602.060 have. what is its precision

ryzh [129]

That number has 6 significant numbers. It's precision would be 602.

Hope it helped.

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3 years ago