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sveta [45]
2 years ago
5

I = [(x + cos2x = )dx​

Mathematics
1 answer:
tester [92]2 years ago
7 0
R we suppose to answer it
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Can anyone answer these? it would be appreciated:)
Aleonysh [2.5K]

Answer:

Step-by-step explanation:

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3 years ago
If a quadrilateral does not have two pairs of opposite sides that are parallel, then it may be a _____.
vivado [14]
It may be a trapezium
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Question 9 of 10
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3 years ago
 Sandra sells necklaces at a school craft fair. She uses the equation P= 7.5n - (2.25n + 15) to determine her total profit at th
gregori [183]
The way you find profit is to subtract the revenue and the cost
Profit = Revenue - Cost
The revenue is the amount of money coming in, the cost is the amount of money going out. The goal of course is to have the revenue larger than the cost so that the profit is positive. 

So the equation given is
P = 7.5n - (2.25n+15)
and its in the form
P = R - C
where...
R = 7.5n is the revenue equation
C = 2.25n+15 is the cost equation

Focus on the revenue equation
R = 7.5n
which is the same as 
R = 7.50*n

This tells us that Sandra pulls in a total of 7.50*n dollars where n is some positive whole number. It represents the number of necklaces sold. For example, if she sold n = 10 necklaces, then
R = 7.50*n
R = 7.50*10
R = 750
meaning that Sandra has made $750 in revenue

As you can see above, the revenue is computed by multiplying the price per necklace ($7.50) by the number of necklaces sold (n) to get R = 7.50*n

So that's why the answer is $7.50

Note: The 2.25 is part of the cost equation. This is known as the variable cost. It is the cost to make one necklace ignoring the fixed cost (eg: rent). The variable cost often doesn't stay the same, but algebra textbooks often simplify this aspect. 
8 0
3 years ago
Ella used 3 fourths of lemons to make one half liters of lemonade. If Ella's recipe is for 1 liter of lemonade, how many lemons
erma4kov [3.2K]

Answer:

6 Total lemons

Step-by-step explanation:

1 1/2 lemons per 1 liter of lemonade

1 1/2 times 4

= 6 total lemons

5 0
3 years ago
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