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stealth61 [152]

3 years ago

14

School guidelines require that there must be at least 2 chaperones for every 25 students going on a school trip. How many chaper

ones must there be for 80 students?
A. 6 chaperones

B. 40 chaperones

C. 3 chaperones

D. 7 chaperones

2 answers:

Ira Lisetskai [31]3 years ago

7 0

We are given that the ratio of chaperon to student is at least 2 chaperon per 25 students. In this case, the number of chaperons of 80 students is 2 chaperon per 25 students * (80 students) equal to 6.4 chaperons .Since only natural numbers are allowed, then the answer should be D.7 chaperons

ivolga24 [154]3 years ago

7 0

The answer is d you would need 7. 6 would only cover 75 students.

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3 years ago

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adelina 88 [10]

Solution :

We have to prove that $\overline{A \cup B} = \overline{A} \cap \overline{B}$ (De-Morgan's law)

Let $x \in \bar{A} \cap \bar{B},$ then $x \in \bar{A}$ and $x \in \bar{B}$

and so $x \notin \bar{A}$ and $x \notin \bar{B}$ .

Thus, $x \notin A \cup B$ and so $x \in \overline{A \cup B}$

Hence, $\bar{A} \cap \bar{B} \subset \overline{A \cup B}$ .........(1)

Now we will show that $\overline{A \cup B} \subset \overline{A} \cap \overline{B}$

Let $x \in \overline{A \cup B}$ ⇒ $x \notin A \cup B$

Thus x is present neither in the set A nor in the set B, so by definition of the union of the sets, by definition of the complement.

$x \in \overline{A}$ and $x \in \overline{B}$

Therefore, $x \in \overline{A} \cap \overline{B}$ and we have $\overline{A \cup B} \subset \overline{A} \cap \overline{B}$ .............(2)

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2 years ago

What is the total surface area of the rectangular pyramid whose net is shown?

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Answer:

95 in.²

Step-by-step explanation:

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Area of triangle = ½*5*7 = 17.5 in.²

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2 years ago

A car traveling east at 40.0 m/s passes a trooper hiding at the roadside. The driver uniformly reduces his speed to 25.0 m/s in

Anni [7]

Step-by-step explanation:

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$a=\dfrac{v-u}{t}$

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3 years ago

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3 years ago