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stealth61 [152]
2 years ago
14

School guidelines require that there must be at least 2 chaperones for every 25 students going on a school trip. How many chaper

ones must there be for 80 students?
A. 6 chaperones

B. 40 chaperones

C. 3 chaperones

D. 7 chaperones
Mathematics
2 answers:
Ira Lisetskai [31]2 years ago
7 0
We are given that the ratio of chaperon to student is at least 2 chaperon per 25 students. In this case, the number of chaperons of 80 students is 2 chaperon per 25 students * (80 students) equal to 6.4 chaperons .Since only natural numbers are allowed, then the answer should be D.7 chaperons 
ivolga24 [154]2 years ago
7 0
The answer is d you would need 7. 6 would only cover 75 students.
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Paul has 12 coins in his pocket, consisting entirely of dimes and quarters. If he has a total of 195 cents in coins, how many co
anyanavicka [17]

Let x be the number of dimes

and y be the number of quarters

Total number of coins = 12

So number of dimes + number of quarters = total number of coins

x + y = 12 ---------> equation 1

We know, 1 Quarter = 25 cents, 1 Dime = 10 cents, total cents = 196

y quarters = 25y cents , x dimes = 10x cents

x dimes + y quarters = 195 cents

10x + 25y = 195 -----------> equation 2

Now solve both equations

x + y =12, we solve for y by subtracting x on both sides

y = 12-x

Now substitute y in second equation

10x + 25(12-x) = 195

10x + 300 -25x = 195 (combine like terms)

-15x + 300 = 195 (subtract 300 on both sides)

-15x = -105 ( divide by -15)

x=7

y= 12-x

y=12-7 = 5

The number of dimes = 7

Number of quarters = 5






8 0
3 years ago
A farmer wishes to fence a rectangular area behind his barn. The barn forms one end of the rectangle and the length of the recta
Semenov [28]
1. The formula for calculate the perimeter of a rectangle, is:

 P=2L+2W

 P is the perimeter of the rectangle (P=320 feet).
 L is the lenght of the rectangle.
 W is the width of the rectangle.
<span>
 2. The problem says that the length of the rectangle is three times the width, so you have:
</span>
 L=3W

 3. When you substitute L=3W and P=320, into P=2L+2W, you obtain:

 P=2L+2W
 320=2(3W)+2W
 320=6W+2W
 8W=320
 W=320/8
 W=40 feet

 4. The barn forms one end of the rectangle. Therefore the linear feet of fence (x) is:

 x=P-W
 x=320 feet-40 feet
 x=280 feet
<span>
 How many linear feet of fence must he buy?
</span>
 The answer is: 280 feet
5 0
3 years ago
Abbey purchased a poster that had a height of 2 feet and a width of 0.7 foot.What is the area of Abbey's poster?
Eduardwww [97]

Answer:

1.4 feet

Step-by-step explanation:

To determine area we multiply height X width

2 X .7 = 1.4

6 0
3 years ago
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Sonja [21]

Answer:

2 and 1/4 liters

Step-by-step explanation:

add them together

3 0
3 years ago
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Mariana walked 3/10 mile to the park. Later, she walked 1/4 mile to a friend's house. Then she walked 2/5 mile home. How many mi
Paladinen [302]

Answer:

19/20 of a mile.

Step-by-step explanation:

\frac{3}{10} + \frac{1}{4} + \frac{2}{5}

The common denominator is 20 so we times the first one by 2 the second one by 5 and the last one by 4. (Both numerator and denominator.)

You will end up with this \frac{6}{20} + \frac{5}{20} + \frac{8}{20} = \frac{19}{20}

7 0
3 years ago
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