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OlgaM077 [116]
1 year ago
14

The temperature was 75 degrees. at noon, the temperature increased by 7. by evening the temperature decreased by 7

Mathematics
1 answer:
DIA [1.3K]1 year ago
6 0

Answer:

75

Step-by-step explanation:

75 + 7 = 82


82 - 7 = 75

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PLEASE HELP!! If the endpoints of have the coordinates A(9, 8) and B(-1, -2), what is the midpoint of ?
dimaraw [331]

M refers to midpoint.

A(9, 8) \\B(-1, -2) \\M(\frac{x_1-x_2}{2}, \frac{y_1-y_2}{2}) \\M(\frac{9-(-1)}{2}, \frac{8-(-2)}{2}) \\M(\frac{10}{2}, \frac{10}{2})\Longrightarrow\boxed{M(5, 5)}

Hope this helps.

r3t40

6 0
3 years ago
Which inequality is true for x=5
Andreyy89

Answer:

The answer is A) 2x+ 5 > 13

Step-by-step explanation:

4 0
2 years ago
What is the slope of a line with endpoints at (3,4) and (2,5)?
Lesechka [4]

\bf (\stackrel{x_1}{3}~,~\stackrel{y_1}{4})\qquad (\stackrel{x_2}{2}~,~\stackrel{y_2}{5}) \\\\\\ slope = m\implies \cfrac{\stackrel{rise}{ y_2- y_1}}{\stackrel{run}{ x_2- x_1}}\implies \cfrac{5-4}{2-3}\implies \cfrac{1}{-1}\implies -1

6 0
2 years ago
Read 2 more answers
( 3 1 ​ ) 2 +3 2 =left parenthesis, start fraction, 1, divided by, 3, end fraction, right parenthesis, squared, plus, 3, squared
Fynjy0 [20]

Answer:

I guess that we have the equation:

(1/3)^2 + 3^2 =

And we want to solve it.

Here just remember that:

3^2 = 3*3 = 9

then:

(1/3)^2 = (1/3)*(1/3) = 1/9

replacing these in the expression, we get:

(1/3)^2 + 3^2 = 1/9 + 9

If we want to write this as a single fraction, we can rewrite:

1/9 + 9 = 1/9 + (9/9)*9

           = 1/9 + 81/9 = (1 + 81)/9 = 82/9

4 0
3 years ago
Create the equation of a quadratic function with a vertex of (5,6) and a y-intercept of -69
Elena L [17]
If the y-intercept is at -69, meaning the point is (0, -69), thus x = 0, y = -69

\bf ~~~~~~\textit{parabola vertex form}
\\\\
\begin{array}{llll}
\boxed{y=a(x- h)^2+ k}\\\\
x=a(y- k)^2+ h
\end{array}
\qquad\qquad
vertex~~(\stackrel{}{ h},\stackrel{}{ k})\\\\
-------------------------------\\\\
vertex~(5,6)\quad 
\begin{cases}
x=5\\
y=6
\end{cases}\implies y=a(x-5)^2+6
\\\\\\
\textit{we also know that }
\begin{cases}
x=0\\
y=-69
\end{cases}\implies -69=a(0-5)^2+6
\\\\\\
-75=25a\implies \cfrac{-75}{25}=a\implies a=-3
\\\\\\
therefore\qquad \boxed{y=-3(x-5)^2+6}
3 0
2 years ago
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