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Annette [7]
3 years ago
13

Please help me with these 3 questions i will mark best answer brainliest!

Mathematics
2 answers:
Agata [3.3K]3 years ago
6 0
I only know #1 which is 0.85
Helga [31]3 years ago
3 0
1. 0.85 and 85/100
2. y= 25
3. g= 14
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A 50-ft chain with mass density 5 lb/ft is initially coiled on the ground. How much work is performed in lifting the chain so th
tatyana61 [14]
Density is mass/ volume so the answer is 10
6 0
2 years ago
−10x + 1 + 7x = 37 i need the answers for that
vaieri [72.5K]
-10x+7x=-3x
3x+1=37
(-1) (-1)
3x=36
(Divide by 3 each side)
3x divided by 3= x
36 divided by 3 = 6
Answer: x=6
4 0
2 years ago
At 10:05 a.m., there are 2 microscopic bacteria cells in the bottle. How many cells will be in the bottle at 10:15 a.m.? A. 2 B.
svet-max [94.6K]

Answer: C. 8

At 10:15 a.m., there are 8 cells in the bottle.

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
Brand X costs $1.65 for 11 ounces. Brand Y costs 2 cents more per ounce. What is the cost of 15 ounces of brand Y?
34kurt

Answer:

$2.25

Step-by-step explanation:

You can find the answer by setting up a simple equation.

Brand X is 1.65 for 11 ounces

we can find the cost of one ounce of Brand X by using division

1.65/11

.15

this means that for every ounce of Brand X, it costs 15 cents

Since brand Y costs two cents more per ounce that would make it be 17 cents per ounce

now all you need to do is multiply and solve.

.15 * 15 = $2.25

8 0
2 years ago
Read 2 more answers
On a baseball field, the pitcher’s mound is 60.5 feet from home plate. During practice, a batter hits a ball 195 feet at an angl
worty [1.4K]

In this problem, we can imagine that all the points connect to form a triangle. The three point or vertices are located on the pitcher mount, the home plate and where the outfielder catches the ball. So in this case we are given two sides of the triangle and the angle in between the two sides.

<span>With the following conditions, we can use the cosine law to solve for the unknown 3rd side. The formula is:</span>

c^2 = a^2 + b^2 – 2 a b cos θ

Where,

a = 60.5 ft

b = 195 ft

θ = 32°

Substituting the given values:

c^2 = (60.5)^2 + (195)^2 – 2 (60.5) (195) cos 32

c^2 = 3660.25 + 38025 – 20009.7

c^2 = 21,675.56

c = 147.23 ft

<span>Therefore the outfielder throws the ball at a distance of 147.23 ft towards the home plate.</span>

8 0
2 years ago
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