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3 years ago

56.53 ___ 565.3 Witch is greater

Mathematics

1 answer:

Naddik [55]3 years ago

5 0

According to my calculation 565.3 is greater.

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I need help with the photo below.

PSYCHO15rus [73]

Here, 30/360 * 2πr = 10
1/12 * 2 * 3.14 * r = 10
r = 10*12 / 6.28
r = 19.11

Now, Area = 1/12 * 3.14 * (19.11)²
= 3.14/12 * 365.16
= 95.5 Ft²

In short, Your Answer would be Option C

Hope this helps!

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2 years ago

Riddle what 3D shape should be afraid of?

Digiron [165]

Well a sphere ok ok :)

4 0

2 years ago

Read 2 more answers

What is the volume of the regular pyramid?

ad-work [718]

Answer:

Step-by-step explanation:

The volume of the regular pyramid is $V=\dfrac{1}{3}A_{base}H.$

The base of given pyramid is regular hexagon with side 12 cm. The are of this hexagon consistsof area of 6 equilateral triangles and is equal to

$A_{base}=6\cdot \dfrac{1}{2}\cdot 12\cdot 10.4=374.4\ cm^2.$

Hence, the volume of the pyramid is

$V=\dfrac{1}{3}\cdot 374.4\cdot 36=4,492.8\ cm^3.$

7 0

3 years ago

Please help me<3 i will give brainliest to the right answer

marysya [2.9K]

Answer:

26.5

Step-by-step explanation:

Because the sales is $530 and the commission rate is 5%, the commission would be 5% of the sales, which would be $26.5

3 0

3 years ago

i need help asap please dont type random anwsers, that will result in it being deleted. GIVING BRAINLIEST ONLY TO CORRECT, INCOR

Veseljchak [2.6K]

Answer:

The area of the rectangle TOUR is 80.00 unit².

Step-by-step explanation:

The area of a rectangle is computed using the formula:

$Area\ of\ a\ Rectangle=length\times width$

Since the dimensions of the rectangle are not provided we can compute the dimensions using the distance formula for two points.

The distance formula using the two point is:

$distance=\sqrt{(x_{2}-x_{1})^{2}+(y_{2}-y_{1})^{2}}$

Considering the rectangle TOUR the area formula will be:

Area of Rectangle TOUR = TO × OU

The co-ordinates of the four vertices of a triangle are:

T = (-8, 0), O = (4, 4), U = (6, -2) and R = (-6, -6)

Compute the distance between the vertices T and O as:

$TO=\sqrt{(4-(-8))^{2}+(4-0)^{2}}\\=\sqrt{12^{2}+4^{2}} \\=\sqrt{160} \\=4\sqrt{10}$

Compute the distance between the vertices O and U as:

$OU=\sqrt{(6-4)^{2}+(-2-4)^{2}}\\=\sqrt{2^{2}+6^{2}} \\=\sqrt{40} \\=2\sqrt{10}$

Compute the area of rectangle TOUR as follows:

$Area\ of\ TOUR=TO\times OU\\=4\sqrt{10}\times 2\sqrt{10}\\=80\\\approx80.00 unit^{2}$

Thus, the area of the rectangle TOUR is 80.00 unit².

6 0

2 years ago