10.) 1 and 2 in this diagram are___

Mathematics

1 answer:

Anastasy [175]2 years ago

3 0

Answer:

Step-by-step explanation:

they are complementary, they add to 90

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Find all angles, 0 ≤C<360 that satisfy the equation below, to the nearest tenth of a degree.

ludmilkaskok [199]

Move all the terms involving the sine to one side, and all the numbers to the other:

$9\sin(c)-2=\sin(c)-7 \iff 8\sin(c) = -5\iff \sin(c)=-\dfrac{5}{8} \iff c = \arcsin\left(-\dfrac{5}{8}\right)\approx 321.3$

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3 years ago

A rectangle has a perimeter of 30 inches.

erastova [34]

The new perimeter would be 60. because the width and the height are doubled.

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3 years ago

(7)(8)(9) Geometry Check Ans 7) s = 15 8) y = 64 x = 99 9) 96

Katyanochek1 [597]

Problem 7: Correct
Problem 8: Correct
Problem 9: Correct

The steps are below if you are curious

===========================================================================================

Problem 7

S = 180*(n-2)
2340 = 180*(n-2)
2340/180 = n-2
13 = n-2
n-2 = 13
n = 13+2
n = 15

I'm using n in place of lowercase s, but the idea is the same. If anything, it is better to use n for the number of sides since S already stands for the sum of the interior angles. I'm not sure why your teacher decided to swap things like that.

===========================================================================================

Problem 8

First find y
y+116 = 180
y+116-116 = 180-116
y = 64

which is then used to find x. The quadrilateral angles add up to 180*(n-2) = 180*(4-2) = 360 degrees
Add up the 4 angles, set the sum equal to 360, solve for x

x+y+125+72 = 360
x+64+125+72 = 360 ... substitution (plug in y = 64)
x+261 = 360
x+261-261 = 360-261
x = 99

===========================================================================================

Problem 9

With any polygon, the sum of the exterior angles is always 360 degrees

The first two exterior angles add to 264. The missing exterior angle is x
x+264 = 360
x+264-264 = 360-264
x = 96

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3 years ago

Consider the following hypothesis test:

Gnom [1K]

Answer:

a. z=3.09. Yes, it can be concluded that the population mean is greater than 50.

b. z=1.24. No, it can not be concluded that the population mean is greater than 50.

c. z=2.22. Yes, it can be concluded that the population mean is greater than 50.

Step-by-step explanation:

We have a hypothesis test for the mean, with the hypothesis:

$H_0: \mu\leq50\\\\H_a:\mu> 50$