25.8%
First, determine how many standard deviations from the norm that 3 tons are. So:
(3 - 2.43) / 0.88 = 0.57/0.88 = 0.647727273
So 3 tons would be 0.647727273 deviations from the norm. Now using a standard normal table, lookup the value 0.65 (the table I'm using has z-values to only 2 decimal places, so I rounded the z-value I got from 0.647727273 to 0.65). The value I got is 0.24215. Now this value is the probability of getting a value between the mean and the z-score. What I want is the probability of getting that z-score and anything higher. So subtract the value from 0.5, so 0.5 - 0.24215 = 0.25785 = 25.785%
So the probability that more than 3 tons will be dumped in a week is 25.8%
Answer: 3/4 x 48
3 x 12
= 36
Got 12 by reducing the numbers with the Greatest Common Factor (GCF) 4
Answer:
11
Step-by-step explanation:
3*(3)^2-16
27-16=11
Answer:
1.8.
Step-by-step explanation:
9 divided by 5 is 1.8.
Answer:
442 miles
Step-by-step explanation:
Given
To properly solve this question, I illustrate some given parameters using attached image
From the image, apply Pythagoras theorem

Differentiate w.r.t time (t)


Divide both sides by 2

From the question, we have that the plan travels are 510mi/h.
This implies that:

So, we then calculate the value of x when the distance (y) is 2mi i.e.:

Apply Pythagoras theorem






So, the expression becomes:








<em>Hence, the distance is 442 miles</em>