Answer:
The answer in the procedure
Step-by-step explanation:
we know that
The rule of the reflection of a point over the y-axis is equal to
A(x,y) ----->A'(-x,y)
That means -----> The x-coordinate of the image is equal to the x-coordinate of the pre-image multiplied by -1 and the y-coordinate of both points (pre-image and image) is the same
so
A(3,-1) ------> A'(-3,-1)
The distance from A to the y-axis is equal to the distance from A' to the y-axis (is equidistant)
therefore
To reflect a point over the y-axis
Construct a line from A perpendicular to the y-axis, determine the distance from A to the y-axis along this perpendicular line, find a new point on the other side of the y-axis that is equidistant from the y-axis
Answer:
y = -34x + 62
Step-by-step explanation:
<u>Use the point slope form: (y - y1) = m(x - x1)</u>
<u />
(y - (-6) = -34(x - 2)
y + 6 - 6 = -34x + 68 - 6
y = -34x + 62
Answer: y = -34x + 62
Step-by-step explanation:
It seems here that they are asking us to solve for x
to do this we first need to factor
Since we can't factor this using the normal method we can instead do this
x^2 -4x-17=0
add 4 to both sides as it is a perfect square
x^2 - 4x + 4 = 17 +4
(x-2)^2 = sqrt 21
x-2 = ± 4.58
x -2 = 4.58 x-2 = -4.58
x= 6.58 x=-2.58
Or just say x=2+√21 or x=2−√21
Step-by-step explanation:
Rise of y-value = (-4) - (3) = -7.
Run of x-value = (8) - (6) = 2.
Slope of the line = Rise / Run = (-7) / (2) = -3.5.
