1 answer:
The solution to the system of equations is (-1, 1) and (1, -1)
<h3>How to determine the solution to the system of equations?</h3>The system of equations is given as:
x^3 + x^2y + xy^2 + y^3 = 0
x^2 + 4y^2 = 5
The equations in the above system of equations are nonlinear equations.
The best way to a system of equations that are nonlinear equations is by the use of graphs
So, we start by plotting the graphs of the equations in the system of equations given as x^3 + x^2y + xy^2 + y^3 = 0 and x^2 + 4y^2 = 5
See attachment for the graph
The point of intersection represents the solution
From the attached graph, the points of intersection of the equations are
(-1, 1) and (1, -1)
Hence, the solution to the system of equations is (-1, 1) and (1, -1)
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Answer:
The practical domain of the function is [30,32].
Step-by-step explanation:
The given function is
where, p(h) represents the Vonda's weekly pay as a function of hours worked.
She pays a one time $250 chair rental fee, and earns $40 per hour that she works.
Domain is the set of all possible inputs.
The possible domain of the given function is all real numbers but the number of hours can not be negative, therefore h>0.
It is given that Vonda works between 30 and 32 hours per week at a hair salon. So,
Therefore practical domain of the function is [30,32].