6. How much heat is lost cooling 25 grams of water from 90°C to 45°C?

Mathematics

1 answer:

sergey [27]2 years ago

8 0

Answer:

4,7025 (kJ).

Step-by-step explanation:

1) according to the condition: m=25 gr.; t₂=90; t₁=45; c=4.18 J/(g°C);

2) the formula of required heat is

Q=c*m*(t₂- t₁);

3) according to the formula of heat:

Q=4.18*25*45=4702.5 (J).

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