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Radda [10]
2 years ago
6

6. How much heat is lost cooling 25 grams of water from 90°C to 45°C?

Mathematics
1 answer:
sergey [27]2 years ago
8 0

Answer:

4,7025 (kJ).

Step-by-step explanation:

1) according to the condition: m=25 gr.; t₂=90; t₁=45; c=4.18 J/(g°C);

2) the formula of required heat is

Q=c*m*(t₂- t₁);

3) according to the formula of heat:

Q=4.18*25*45=4702.5 (J).

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Answer:

Step-by-step explanation:

Check attachment for solution

4 0
3 years ago
At the city Museum child admission is $5.30 and adult admission is $9.30 on Sunday 146 tickets were sold for a total sales of $1
DerKrebs [107]

Answer:

The number of child tickets is 53

And adult tickets sold out is 93

Step-by-step explanation:

Let the child tickets be x

And the adult tickets be y

x+y = 146 - - - - - - - 1

x= 146-y

5.3x + 9.3y= 1145.80 - - - - - 2

We can substitute x= 146-y in equation 2

5.3(146-y) + 9.3y= 1145.80 - -- 2

773.8 - 5.3y +9.3y = 1145.80

773.8+4y= 1145.80

4y= 1145.80-773.8

4y= 372

y= 372/4

y= 93

We can now substitute y= 93 in equation 1 to find x

x+ 93= 146

x= 146-93

x= 53

Hence

The number of child tickets is 53

And adult tickets sold out is 93

6 0
3 years ago
Graph y=(x-2)^2-16 . Please help?!
Sauron [17]

Answer:

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4 0
3 years ago
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7 0
3 years ago
Gary drove to the park at a rate of 50 miles per hour if it took him 2.5 hours to get from his house to the park how far away is
Marina86 [1]

Answer:

The distance of the park from the Gary's house is 125 miles.

Step-by-step explanation:

Speed of Gary = 50 miles/hour

Time taken by Gary to reach the park from his house = 2.5 hours

Now, we know that,

Distance travelled = speed × time

So,  distance between park and Gary's house = speed × time

= 50 × 2.5

= 125 miles

So, the park is 125 miles away from the Gary's house.

4 0
3 years ago
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