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1 year ago

Brown: Dilate triangle BCD with B(-4,-2)C(0, 2), and D(2, -4) using a scale factor of 5/2. What are the coordinates of D'?

Mathematics

1 answer:

inessss [21]1 year ago

7 0

We get the coordinates of D' as (5, -10).

We have a triangle BCD.

We are given the coordinates as:

B(-4,-2) C(0, 2), and D(2, -4)

we will first find the distance between the points to get the sides of the triangle.

BC² = ( 0 + 4)² + (2 + 2)²

BC² = 16 + 16

BC = 4√2

CD² = (2 - 0)² + (-4 - 2)²

CD² = 4 + 36

CD = 2√10

BD² = (2 + 4)² + ( -4 + 2)²

BD² = 36 + 4

BD = 2√10

Now, we use a scale factor of 5 / 2.

So he coordinates of D' will be:

D' = ( 2 × 5 / 2 , -4 × 5 / 2 )

D' =( 5, -10)

Therefore, we get the coordinates of D' as (5, -10).

Learn more about coordinates here:

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see the attached figure
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Brown: Dilate triangle BCD with B(-4,-2)C(0, 2), and D(2, -4) using a scale factor of 5/2. What are the coordinates of D'?​

Brown: Dilate triangle BCD with B(-4,-2)C(0, 2), and D(2, -4) using a scale factor of 5/2. What are the coordinates of D'?