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Rashid [163]
1 year ago
10

Brown: Dilate triangle BCD with B(-4,-2)C(0, 2), and D(2, -4) using a scale factor of 5/2. What are the coordinates of D'?​

Mathematics
1 answer:
inessss [21]1 year ago
7 0

We get the coordinates of D' as (5, -10).

We have a triangle BCD.

We are given the coordinates as:

B(-4,-2) C(0, 2), and D(2, -4)

we will first find the distance between the points to get the sides of the triangle.

BC² = ( 0 + 4)² + (2 + 2)²

BC² = 16 + 16

BC = 4√2

CD² = (2 - 0)² + (-4 - 2)²

CD² = 4 + 36

CD = 2√10

BD² = (2 + 4)² + ( -4 + 2)²

BD² = 36 + 4

BD = 2√10

Now, we use a scale factor of 5 / 2.

So he coordinates of D' will be:

D' = ( 2 × 5 / 2 , -4 × 5 / 2 )

D' =( 5, -10)

Therefore, we get the coordinates of D' as (5, -10).

Learn more about coordinates here:

brainly.com/question/12959377

#SPJ9

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Answer:

<h3>p = 131.25</h3>

Step-by-step explanation:

The variation p varies directly with T is written as

p = kT

where k is the constant of proportionality

To find p when T =500 we must first find the formula for the variation

That's

when p = 105 and T = 400

105 = 400k

Divide both sides by 400

<h3>k =  \frac{21}{80}</h3>

So the formula for the variation is

<h2>p =  \frac{21}{80} T</h2>

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Substitute it into the above formula

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p =  \frac{21}{80}  \times 500

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The final answer is

<h3>p = 131.25</h3>

Hope this helps you

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