X^2 + x - 6
------------- <= 0
x - 7
(x + 3)(x - 2)
---------------- <= 0
x - 7
2 critical values are x = -3 and x = 2
if x <= -3 the the function <= 0 so that's one part of the solution
also x >= 2
x must be < 7 if its = 7 then the function is indeterminate. and values between 2 and 7 will give negative valu to function
The answer is choice A.
Answer:
f(x) = 3 cos (2Pi / period value ; x )+ 2
or see answer using 2 as the period see answer in bold below.
Step-by-step explanation:
cosine function amplitude of 3 is A = 3
The period is used to find B
You need to show period value as the denominator and work out from there with 2PI as a function numerator to show as 2pi / period can be a data angle
C is the adding value.
Acos (Bx) + C
A = 3
Bx = 2 pi / period
C = + 2
However f 2 is also the period found
then we just plug in 2 to above formula
f(x) = 3 cos (2Pi / 2 ; x )+ 2
f(x) = 3cos (x pi) + 2
Answer:
C. -2x+10
Step-by-step explanation:
When you multiply a negative with a negative, it becomes a positive.
Answer:
If you've learnt sin(A+B) = sinAcosB + cosAsinB,
sin(4u)
= sin(2u+2u)
= sin(2u)cos(2u) + cos(2u)sin(2u)
= 2 sin(2u) cos(2u).
Answer:
Step-by-step explanation:
Ivan and 3 others were evenly matched.
1+3=4
So there were 4 grandmas on the other team. :)