Given expression is 35, 36, 37, 38...
First term a = 35
Common difference d = 36-35 = 1
Nth term of arithmetic sequence is:


To find the 100th term, substitute n = 100


Correct option is B
Do you mean a_(n+1), worded a sub (n+1)?
If so yes. If the function of the sequence is getting smaller or more negative with each term.
Answer:
Step-by-step explanation:
You need to find the HCF of 36 and 90.
<u>Prime factors of each:</u>
<u>HCF includes all prime factors of both numbers:</u>
- HCF(36, 90) = 2*2*3*3*5 = 180
X
+
6
−
5
=
8
−
2
+
6
−
5
=
8
−
2
Solve
1
Subtract the numbers
x
+
6
−
5
=
8
−
2
+
6
−
5
=
8
−
2
x
+
1
=
8
−
2
+
1
=
8
−
2
2
Subtract the numbers
x
+
1
=
8
−
2
+
1
=
8
−
2
x
+
1
=
6
+
1
=
6
3
Subtract
1
1
from both sides
x
+
1
=
6
+
1
=
6
x
+
1
−
1
=
6
−
1
+
1
−
1
=
6
−
1
4
Simplify
Subtract the numbers
Subtract the numbers
x
=
5
=
5