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Dovator [93]
2 years ago
11

Simplify 16-4 [3+2÷(9-7)

Mathematics
2 answers:
elena-14-01-66 [18.8K]2 years ago
5 0
16 - 4 [ 3 + 2 / (9 - 7)]
16 - 4 [ 3 + 2 / 2)]
16 - 4 [ 3 + 1 ]
16 - 4 [4]
16 - 16
0 <===
pav-90 [236]2 years ago
5 0
Hello,
 according to bodmas rule

16-4[3+2/2]
=16-4[5/2]
=16-(20/2)
=16-10
=6

thats the answer
 bye!!
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An archaeologist is categorizing the artifacts he has discovered. Two-thirds of the artifacts are shards of pottery. One-eighth
Reika [66]

Answer:

Personal items=15

Step-by-step explanation:

We are given:

Total number of artifacts = 72.

We are told that 2/3 of total artifacts are shards of pottery.

\text{Shards of pottery}=72*\frac{2}{3} =24*2=48

We are also told that 1/8 of total artifacts are tools.

\text{Tools}=72*\frac{1}{8}=9

Now we will find out number of personal items by subtracting combined number of shards of pottery and tools from total number of artifacts.

\text{ Personal items}=72-(48+9)

\text{ Personal items}=72-57=15

Therefore, there are 15 personal items.

8 0
3 years ago
Does anyone know the answer to the last question? :)
PIT_PIT [208]

Answer:

y=1.5 that what i got okay

6 0
2 years ago
In 1859, 24 rabbits were released into the wild in Australia, where they had no natural predators. Their population grew exponen
Mashcka [7]

Answer:

a) P' = P

   P(t) = 24e^{0.693t} where t is step of 6 months

b) 7.7 years

c)1064.67 rabbits/year

Step-by-step explanation:

The differential equation describing the population growth is

\frac{dP}{dt} = P

Where t is the range of 6 months, or half of a year.

P(t) would have the form of

P(t) = P_0e^{kt}

where P_0 = 24 is the initial population

After 6 month (t = 1), the population is doubled to 48

P(1) = 24e^k = 48

e^k = 2

k = ln(2) = 0.693

Therefore P(t) = 24e^{0.693t}

where t is step of 6 months

b. We can solve for t to get how long it takes to get to a population of 1,000,000:

24e^{0.693t} = 1000000

e^{0.693t} = 1000000 / 24 = 41667

0.693t = ln(41667) = 10.64

t = 10.64 / 0.693 = 15.35

So it would take 15.35 * 0.5 = 7.7 years to reach 1000000

c. P' = P_0ke^{kt}

We need to resolve for k if t is in the range of 1 year. In half of a year (t = 0.5), the population is 48

24e^{0.5k) = 48

0.5k = ln2 = 0.693

k = 1.386

Therefore, P' = 1.386*24e^{1.386t}

At the mid of the 3rd year, where t = 2.5, we can calculate P'

P' = 1.386*24e^{1.386*2.5} = 1064.67 rabbits/year

4 0
3 years ago
Find the equation of a line parallel to y - 5x = 10 that passes through the point (3, 10). (answer in slope-intercept form)
Maru [420]
I think it would be the second one
8 0
3 years ago
Read 2 more answers
Witch Decimal is equal to six-tenths?<br><br> 0.6 0.15 0.2 0.3 0.4
miss Akunina [59]
0.6 matches with six-tenths because if you divide 6 and 10 together you will get 0.6

Hope this helped! :)

~Shadow 
6 0
3 years ago
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