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2 years ago

PLEASE HELP

Mathematics

1 answer:

sweet [91]2 years ago

8 0

Answer:

a) $2 + 3 + 5 + 6 = 16$

b) $8a + b-9$

c) $8a - 28b + 15c$

Step-by-step explanation:

We are given the following in the question:

1. Equivalent expression

$2 + 3 + 5 + 6$

Since all the terms are like terms, we can write,

$2 + 3 + 5 + 6 = 16$

2. Sum of given expression

$(8a - 2b - 4) \text{ and } (3b - 5)\\ (8a - 2b - 4) + (3b -5)\\= 8a -2b -4 + 3b -5\\\text{Collecting the like terms}\\8a + (-2b+3b) + (-4-5)\\= 8a + b-9$

3. Standard form of the expression

$4(2a) + 7(-4b) + (3 \times c \times 5)\\=(8a) + (-28b) + (15c)\\=8a - 28b + 15c$

which is the required standard form of the given expression.

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Step-by-step explanation:

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