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exis [7]
2 years ago
12

Roster form {-2,-1,0,1,2,3} set builder form

Mathematics
1 answer:
Fudgin [204]2 years ago
6 0

Answer:0-1 1 -2 2 3

Step-by-step explanation:

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Write an algebraic expression for the following word expression.
sladkih [1.3K]

Answer:

3m + 13 = 31 I hope this helps you!

5 0
3 years ago
Point C,D and E are collinear on CE, and CD:DE = 3/5. C is located at (1,8), D is located (4,5), and E is located at (x,y)
Ugo [173]
Point c and d are the xy factor
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3 years ago
V= u + at<br><br> U=1 <br> T= 1/2 <br> a=-3<br><br> Work out the value of v.
svetoff [14.1K]
1 + -3 1/2 is = to -2.5 so v= -2.5
3 0
2 years ago
Read 2 more answers
Find the exponential function that satisfies the given conditions:
Nady [450]

Answer:

f(t) = 66·0.995^t

Step-by-step explanation:

You can try t=0 and t=1 in each of the formulas to see which one gives values of 66 and 0.5% less than 66, or 65.67.

The first function has an initial value of 0.5, so is not correct.

The second function gives f(1) = 99, so is not correct.

The third function gives f(1) = 65.67, so is correct.

The fourth function gives f(1) = 66.33, so is not correct.

_____

You can realize that the multiplier will be 0.5% less than 100%, so will be 99.5% = 0.995. This number shows up only in the third selection.

4 0
4 years ago
Is it mathematically correct to say that:
Step2247 [10]

Answer: Yes

Step-by-step explanation:

    Since the numerator is multiplying square root 13 by square root 2, we can break them apart.

\displaystyle \frac{\sqrt{13*2}}{\sqrt{13}} =\frac{\sqrt{13}*\sqrt{2}  }{\sqrt{13}}

   You are correct, \sqrt{13} over  \sqrt{13} is equal to one, so we can "cancel them out" of our expression.

\displaystyle \frac{\sqrt{13} }{\sqrt{13}} = 1

   This leaves us with: \sqrt{2}<em />

<em />

<em>We can also test this by using a calculator:</em>

<em />\frac{\sqrt{13*2}}{\sqrt{13}} \approx 1.41421356\\\sqrt{2} \approx 1.41421356\\1.41421356=1.41421356

8 0
2 years ago
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