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maria [59]
2 years ago
6

How do i solve m - 4/9 = -2 67/90

Mathematics
1 answer:
Diano4ka-milaya [45]2 years ago
3 0

Answer:

m=-23/10

Step-by-step explanation:

-2 67/90=-247/90

m-4/9=-247/90

m=-247/90+4/9

m=-247/90+40/90

m=-207/90

m=-23/10

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matrenka [14]

Answer:

i think the second answer

Step-by-step explanation:

6 0
2 years ago
Read 2 more answers
Solve each system by elimination.<br> 1) 10x + 7y=9 -4x - 7y=9
stellarik [79]

Answer:

(3, -3)

Step-by-step explanation:

When asked to solve by elimination, you put them on top of one another, like you're going to add it.

10x + 7y = 9

-4x - 7y = 9

See that 7y? You can cancel those out because one is negative, and one is positive. So those are gone. You finish adding the rest of the numbers as usual and solve for x.

6x = 18

x = 3

Take x, and plug it into either equation to find y.

10(3) + 7y = 9

7y = -21

y = -3

(3, -3)

Hope this helped!

8 0
2 years ago
3. At noon Lan is in his blue mini-van 300 km north of Makenna in her Bugatti. Lan heads south
LiRa [457]

Answer:

The rate at which the distance between them is changing at 2:00 p.m. is approximately 1.92 km/h

Step-by-step explanation:

At noon the location of Lan = 300 km north of Makenna

Lan's direction = South

Lan's speed = 60 km/h

Makenna's direction and speed = West at 75 km/h

The distance  Lan has traveled at 2:00 PM = 2 h × 60 km/h = 120 km

The distance north between Lan and Makenna at 2:00 p.m = 300 km - 120 km = 180 km

The distance West Makenna has traveled at 2:00 p.m. = 2 h × 75 km/h = 150 km

Let 's' represent the distance between them, let 'y' represent the Lan's position north of Makenna at 2:00 p.m., and let 'x' represent Makenna's position west from Lan at 2:00 p.m.

By Pythagoras' theorem, we have;

s² = x² + y²

The distance between them at 2:00 p.m. s = √(180² + 150²) = 30·√61

ds²/dt = dx²/dt + dy²/dt

2·s·ds/dt = 2·x·dx/dt + 2·y·dy/dt

2×30·√61 × ds/dt = 2×150×75 + 2×180×(-60) = 900

ds/dt = 900/(2×30·√61) ≈ 1.92

The rate at which the distance between them is changing at 2:00 p.m. ds/dt ≈ 1.92 km/h

5 0
2 years ago
A school has 3400 students. They conduct a random sample of 124 students and find that 38 of them hate the school.
Contact [7]

Answer:

a) We need a sample size of at least 2401.

b) We need a sample size of at least 1936.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of , and a confidence level of , we have the following confidence interval of proportions.

In which

z is the zscore that has a pvalue of .

The margin of error is:

95% confidence level

So , z is the value of Z that has a pvalue of , so .

(a) you are unwilling to predict the proportion value at your school and​

We use , which is when we are going to need the largest sample size.

So we need to find We need a sample size of at least 2401.

(b) you use the results from the surveyed school as a guideline.

Now the same calculation, just with . So

We need a sample size of at least 1936.

5 0
2 years ago
Pleasee helppp insert two arithnetic means between -5 and 1
Salsk061 [2.6K]

Answer:

a₂ = -3

a₃  = -1

Step-by-step explanation:

We have to  insert two arithmetic means between -5 and 1

Let a₁ and b₂ be the two arithmetic means between -5 and 1

-5, a₂, a₃, 1

Here,

  • a₄ = 1
  • a₁ = -5

We know that the nth term of an Arithmetic sequence

aₙ = a₁ + (n-1)d

a₄ = -5 + (4-1)d

1 = -5 + 3d    

1  + 5 = 3d

3d = 6

Dividing both sides by 2

d = 2

Also

a₂ = a₁ + (2-1)d

a₂ = -5 + d

a₂ = -5 + 2          ∵ d = 2

a₂  = -3

a₃ = a₁ + (3-1)d

a₃  = -5 + 2d

a₃  = -5 + 2(2)   ∵ d = 2

a₃  = -5 + 4

a₃  = -1

Thus,

a₂ = -3

a₃  = -1

Thus, the sequence becomes:

-5, -3, -3, 1

3 0
2 years ago
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