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Alex787 [66]
3 years ago
9

A garden shop charges $72 for 3 rose bushes and 2 lilac bushes. It also charges $114 for 5 rose bushes and 3 lilac bushes. At th

ese same rates, how much would the garden shop charge for 1 rose bush and 1 lilac bush?
Mathematics
2 answers:
jeka943 years ago
3 0
They would charge $28.80 for 1 rose bush and 1 lilac bush. $72/5 flower bushes = $14.40. Thats the price of one bush. Since you're getting 2 bushes, multiply that by 2, and get 28.80.
wlad13 [49]3 years ago
3 0

Answer:

Amount charges for 1 rose bush = \$12

Amount charges for 1 lilac bush = \$18

Step-by-step explanation:

Let x denotes cost of one rose bush and y denotes cost of one lilac bush.

Given statement 1: A garden shop charges $72 for 3 rose bushes and 2 lilac bushes.

we get ,

3x+2y = 72   ....(i)

Given statemnet 2: A garden shop charges $114 for 5 rose bushes and 3 lilac bushes.

we get ,

5x+3y=114      ...(ii)

From equation1, x=\frac{72-2y}{3}

On this value of x in equation (ii), we get

5\left ( \frac{72-2y}{3} \right )+3y=114\\360-10y+9y=342\\y=360-342\\=18\\\Rightarrow x=\frac{72-2y}{3}\\=\frac{72-2(18)}{3}\\=\frac{72-36}{3}\\=\frac{36}{3}\\\\=12

So,

Amount charges for 1 rose bush = \$12

Amount charges for 1 lilac bush = \$18

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3 years ago
Do these ratios form a proportion?<br> $42 per 33 customers<br> $28 per 22 customers<br> yes<br> no
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8 0
2 years ago
Read 2 more answers
Enos took out a 25-year loan for $135,000 at an APR of 6.0%, compounded monthly, and he is making monthly payments of $869.81. W
Alborosie
Present value = 135000
Monthly interest, i = 0.06/12 = 0.005
Monthly payment, A= 869.81

Future value of loan after 16 years
F=P(1+i)^n      [compound interest formula]
=135000(1+.005)^{16*12}
=351736.652

Future value of payments after 16 years
\frac{A((1+i)^n-1)}{i}
=\frac{869.81((1+0.005)^{16*12}-1)}{0.005}
=279287.456

Balance = future value of loan - future value of payments
=351736.652-279288.456
= $ 72448.20

Note: the exact monthly payment for a 25-year mortgage is
A=\frac{P(i*(1+i)^n)}{(1+i)^n-1}
=\frac{135000(0.005*(1+0.005)^{25*12}}{(1+0.005)^{25*12}-1}
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Repeating the previous calculation with this "exact" monthly payment gives
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So we conclude that the exact value obtained above differs from the answer choices is due to the precision (or lack of it) of the provided data.

The closest choice is therefore <span>$72,449.19</span>
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2 years ago
Read 2 more answers
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