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kolezko [41]
2 years ago
8

Sum of x and it’s square is equal to y times z

Mathematics
1 answer:
ludmilkaskok [199]2 years ago
3 0

The algebraic representation of the statement is x + x² - yz = 0

<h3>What are algebraic expressions?</h3>

Algebraic expressions brings the idea of creating or expressing numbers using letters or alphabets without specifying their actual values.

From the information given , we have that;

  • sum of x and it's square = x + x²
  • Equal to y × z

Now, let's equate the expressions;

x + x² = y × z

x + x ² = yz

Let's make into quadratic form

x + x² - yz = 0

Thus, the algebraic representation of the statement is x + x² - yz = 0

Learn more about algebraic expressions here:

brainly.com/question/723406

#SPJ1

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Answer:

D. undefined

General Formulas and Concepts:

<u>Calculus</u>

Derivatives

Derivative Notation

Derivative of a constant is 0

Basic Power Rule:

  • f(x) = cxⁿ
  • f’(x) = c·nxⁿ⁻¹

Derivative Rule [Chain Rule]:                                                                                 \displaystyle \frac{d}{dx}[f(g(x))] =f'(g(x)) \cdot g'(x)

Trig Derivative:                                                                                                       \displaystyle \frac{d}{dx}[sinu] = u'cosu

Derivatives of Parametrics:                                                                                   \displaystyle \frac{dy}{dx} = \frac{\frac{dy}{dt}}{\frac{dx}{dt}}

Step-by-step explanation:

<u>Step 1: Define</u>

\displaystyle \frac{dx}{dt} = 5

\displaystyle \frac{dy}{dt} = sin(t^2)

<u>Step 2: Differentiate</u>

  1. [x Derivative] Basic Power Rule:                                                                   \displaystyle \frac{d^2x}{dt^2} = 0
  2. [y Derivative] Trig Derivative [Chain Rule]:                                                 \displaystyle \frac{d^2y}{dt^2} = cos(t^2) \cdot \frac{d}{dt}[t^2]
  3. [y Derivative] Basic Power Rule:                                                                   \displaystyle \frac{d^2y}{dt^2} = cos(t^2) \cdot 2t^{2 - 1}
  4. [y Derivative] Simplify:                                                                                   \displaystyle \frac{d^2y}{dt^2} = 2tcos(t^2)
  5. [Derivative] Rewrite:                                                                                     \displaystyle \frac{d^2y}{dx^2} = \frac{2tcos(t^2)}{0}

Anything divided by 0 is undefined.

Topic: AP Calculus BC (Calculus I/II)

Unit: Differentiation with Parametrics

Book: College Calculus 10e

5 0
3 years ago
Odette knows that segment KN || segment LM. She wants to use the definition of a
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Step-by-step explanation:

we know that a parallelogram always have two pairs of opposite sides that are parallel and therefore the slopes of the opposite sides must be same to be parallel to each other.

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3 years ago
(01.04 MC)The elevation of city A is 80 feet below sea level; the elevation of city C is 16 feet below sea level. The elevation
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A) The expression to represent the elevation in feet of city D is; ¹/₂ × (-16) ft

B) The solution to the expression of the elevation of City D is; -8 fr which is negative because it falls below sea level.

First of all, sea level is at 0 ft.

Thus;

If city A has an elevation of 80 ft below sea level, then;

Elevation of city A = -80 ft

The elevation of city C is 16 feet below sea level. Thus;

Elevation of city C = -16 ft

A) The elevation of city D is ¹/₂ of the elevation of city C. Thus;

Expression for Elevation of city D = ¹/₂ × (-16)

B) Solving the expression for elevation of city D gives;

Elevation of City D = -8 ft

The reason why the answer is negative is because any distance below sea level is considered to be negative and city C which is twice the elevation of city D is negative, and so city D must also have a negative elevation.

Read more about below sea level elevations at; brainly.com/question/14837848

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3 years ago
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Answer:

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Step-by-step explanation:

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