Subtract (x² + 5x – 6) – (3x^2 – 7x + 1). What is the difference?

A farmer can harvets 2 1/3 acres of corn in 1 day. How many days will it take to harvest 10 1\2 acres

Rus_ich [418]

$10 \frac{1}{2} \div2 \frac{1}{3} = \frac{21}{2} \div \frac{7}{3} = \frac{21}{2} \times \frac{3}{7} = \frac{9}{2} = 4 \frac{1}{2}$
Ans: He will take 4 1/2 days to harvest 10 1/2 acres.

6 0

3 years ago

Rocio drops a ball from a height of 4 meters. Rocio observes that each time the ball bounces, it reaches a peak height which is

docker41 [41]

The exponential equation that correctly models the ball's peak height, h, in meters, after b bounces is given by:

$H(b) = 4(0.79)^b$

<h3>What is an exponential function?</h3>

A decaying exponential function is modeled by:

$A(t) = A(0)(1 - r)^t$

In which:

A(0) is the initial value.

r is the decay rate, as a decimal.

In this problem:

Rocio drops a ball from a height of 4 meters, hence A(0) = 4.

Each time the ball bounces, it reaches a peak height which is 79% of the previous peak height, hence 1 - r = 0.79.

Thus, the equation is given by:

$H(b) = 4(0.79)^b$

More can be learned about exponential equations at brainly.com/question/25537936

4 0

2 years ago

Write each power as a product of factors 2^4 4^2 9^2 8^5 5^3 7^3

snow_lady [41]

 $2^{4}$ ⇒2×2×2×2⇒16
 $4^{2}$ ⇒4×4⇒16
 $9^{2}$ ⇒9×9⇒81
 $8^{5}$ ⇒8×8×8×8×8⇒32.768
 $5^{3}$ ⇒5×5×5⇒125
 $7^{3}$ ⇒7×7×7⇒343

5 0

3 years ago

Find dy/dx x^3+y^3=18xy

tatyana61 [14]

Differentiate both sides of the equation.ddx(x3+y3)=ddx(18xy)ddx(x3+y3)=ddx(18xy)Differentiate the left side of the equation.Tap for fewer steps...By the Sum Rule, the derivative of x3+y3x3+y3 with respect to xx is ddx[x3]+ddx[y3]ddx[x3]+ddx[y3].ddx[x3]+ddx[y3]ddx[x3]+ddx[y3]Differentiate using the Power Rule which states that ddx[xn]ddx[xn] is nxn−1nxn-1 where n=3n=3.3x2+ddx[y3]3x2+ddx[y3]Evaluate ddx[y3]ddx[y3].Tap for more steps...3x2+3y2ddx[y]3x2+3y2ddx[y]Differentiate the right side of the equation.Tap for fewer steps...Since 1818 is constant with respect to xx, the derivative of 18xy18xy with respect to xx is 18ddx[xy]18ddx[xy].18ddx[xy]18ddx[xy]Differentiate using the Product Rule which states that ddx[f(x)g(x)]ddx[f(x)g(x)] is f(x)ddx[g(x)]+g(x)ddx[f(x)]f(x)ddx[g(x)]+g(x)ddx[f(x)] where f(x)=xf(x)=x and g(x)=yg(x)=y.18(xddx[y]+yddx[x])18(xddx[y]+yddx[x])Rewrite ddx[y]ddx[y] as ddx[y]ddx[y].18(xddx[y]+yddx[x])18(xddx[y]+yddx[x])Differentiate using the Power Rule which states that ddx[xn]ddx[xn] is nxn−1nxn-1 where n=1n=1.18(xddx[y]+y⋅1)18(xddx[y]+y⋅1)Multiply yy by 11 to get yy.18(xddx[y]+y)18(xddx[y]+y)Simplify.Tap for more steps...18xddx[y]+18y18xddx[y]+18yReform the equation by setting the left side equal to the right side.3x2+3y2y'=18xy'+18y3x2+3y2y′=18xy′+18ySince 18xy'18xy′ contains the variable to solve for, move it to the left side of the equation by subtracting 18xy'18xy′ from both sides.3x2+3y2y'−18xy'=18y3x2+3y2y′-18xy′=18ySince 3x23x2 does not contain the variable to solve for, move it to the right side of the equation by subtracting 3x23x2 from both sides.3y2y'−18xy'=−3x2+18y3y2y′-18xy′=-3x2+18yFactor 3y'3y′ out of 3y2y'−18xy'3y2y′-18xy′.Tap for fewer steps...Factor 3y'3y′ out of 3y2y'3y2y′.3y'(y2)−18xy'=−3x2+18y3y′(y2)-18xy′=-3x2+18yFactor 3y'3y′ out of −18xy'-18xy′.3y'(y2)+3y'(−6x)=−3x2+18y3y′(y2)+3y′(-6x)=-3x2+18yFactor 3y'3y′ out of 3y'y2+3y'(−6x)3y′y2+3y′(-6x).3y'(y2−6x)=−3x2+18y3y′(y2-6x)=-3x2+18yDivide each term by y2−6xy2-6x and simplify.Tap for fewer steps...Divide each term in 3y'(y2−6x)=−3x2+18y3y′(y2-6x)=-3x2+18y by y2−6xy2-6x.3y'(y2−6x)y2−6x=−3x2y2−6x+18yy2−6x3y′(y2-6x)y2-6x=-3x2y2-6x+18yy2-6xReduce the expression by cancelling the common factors.Tap for more steps...3y'=−3x2y2−6x+18yy2−6x3y′=-3x2y2-6x+18yy2-6xSimplify the right side of the equation.Tap for more steps...3y'=−3(x2−6y)y2−6x3y′=-3(x2-6y)y2-6xDivide each term by 33 and simplify.Tap for fewer steps...Divide each term in 3y'=−3(x2−6y)y2−6x3y′=-3(x2-6y)y2-6x by 33.3y'3=−3(x2−6y)y2−6x33y′3=-3(x2-6y)y2-6x3Reduce the expression by cancelling the common factors.Tap for more steps...y'=−3(x2−6y)y2−6x3y′=-3(x2-6y)y2-6x3Simplify the right side of the equation.Tap for more steps...y'=−x2−6yy2−6xy′=-x2-6yy2-6xReplace y'y′ with dydxdydx.dydx=−x2−6yy2−6x

6 0

3 years ago

Plz help I need to graduate 15 pls!

vredina [299]

The answer is A because X can’t have the same numbers for it to be a function.

6 0

3 years ago