Answer:
0.675 m/s
Step-by-step explanation:
Let height of shadow= y,CD=x
Height of man=2 m
Speed of man= 

Therefore, 


Differentiate w.r.t t



When the man is 4 m from the building
Then, we have x=12-4=8 m

Substitute the values in above equation then, we get


Substitute the values then we get

Hence, the length of his shadow on the building decreasing at the rate 0.675 m/s.
Answer:
Step-by-step explanation:
THANKS 4 POINTS!!!!!!!
Use the Quadratic formula,
x= -b +/- sqrt(b^2-4ac)
-------------------------
2a
x= 4 +/- sqrt(16+12)
----------------------
-6
x = 4+/- sqrt(28)
---------------
-6
x = 4 +/- 2*sqrt(7)
------------------
-6
x= 2(2+/- sqrt(7))
------------------
2(-3)
x= 2+/- sqrt(7)
--------------
-3
48 on call = 3.5 hours for 10 dollars = 1/2 hours for 1.5
Answer:
20
Step-by-step explanation: