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2 years ago

Does anyone know how to this cause I need to know how to do it.

Mathematics

2 answers:

ANEK [815]2 years ago

6 0

Those lines mean absolute value which always positive.
|-3| + 7 could be re-written as 3 + 7
|-3 + 7| could be re-written as 3 + 7

JulsSmile [24]2 years ago

5 0

Answer:

(a)= 10

(b)=4

Step-by-step explanation:

the lines are absolute value, so anything in the lines will be positive

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Sanjay had a case of 24 bottles of water. In the first week Sanjay drank 3/8 of the bottles of water. In the second week Sanjay

Gnom [1K]

Answer:

The answer to your question is: 5 bottles

Step-by-step explanation:

Process

First week

Divide 24 by 8

24/8 = 3 bottles = 1/8

but Sanjay drank 3/8 = 9 bottles

And there are 24 - 9 bottles left = 15

- Second week

Divide 15 by 3

15/3 = 5 then 5 bottles = 1/3

but sanjay drank 2/3 = 10 bottles

Then, there are 15 - 10 bottles left = 5

8 0

3 years ago

Solve for x. 5x - 4 = -3x + 12

Dmitriy789 [7]

Step-by-step explanation:

5x+3x=12+4

8x=16

x=16÷8

x=2

5 0

3 years ago

Read 2 more answers

Can someone check whether its correct or no? this is supposed to be the steps in integration by parts

Gwar [14]

Answer:

$\displaystyle - \int \dfrac{\sin(2x)}{e^{2x}}\: \text{d}x=\dfrac{\sin(2x)}{4e^{2x}}+\dfrac{\cos(2x)}{4e^{2x}}+\text{C}$

Step-by-step explanation:

$\boxed{\begin{minipage}{5 cm}\underline{Integration by parts} \\\\$\displaystyle \int u \dfrac{\text{d}v}{\text{d}x}\:\text{d}x=uv-\int v\: \dfrac{\text{d}u}{\text{d}x}\:\text{d}x$ \\ \end{minipage}}$

Given integral:

$\displaystyle -\int \dfrac{\sin(2x)}{e^{2x}}\:\text{d}x$

$\textsf{Rewrite }\dfrac{1}{e^{2x}} \textsf{ as }e^{-2x} \textsf{ and bring the negative inside the integral}:$

$\implies \displaystyle \int -e^{-2x}\sin(2x)\:\text{d}x$

Using <u>integration by parts</u>:

$\textsf{Let }\:u=\sin (2x) \implies \dfrac{\text{d}u}{\text{d}x}=2 \cos (2x)$

$\textsf{Let }\:\dfrac{\text{d}v}{\text{d}x}=-e^{-2x} \implies v=\dfrac{1}{2}e^{-2x}$

Therefore:

$\begin{aligned}\implies \displaystyle -\int e^{-2x}\sin(2x)\:\text{d}x & =\dfrac{1}{2}e^{-2x}\sin (2x)- \int \dfrac{1}{2}e^{-2x} \cdot 2 \cos (2x)\:\text{d}x\\\\& =\dfrac{1}{2}e^{-2x}\sin (2x)- \int e^{-2x} \cos (2x)\:\text{d}x\end{aligned}$

$\displaystyle \textsf{For }\:-\int e^{-2x} \cos (2x)\:\text{d}x \quad \textsf{integrate by parts}:$

$\textsf{Let }\:u=\cos(2x) \implies \dfrac{\text{d}u}{\text{d}x}=-2 \sin(2x)$

$\textsf{Let }\:\dfrac{\text{d}v}{\text{d}x}=-e^{-2x} \implies v=\dfrac{1}{2}e^{-2x}$

$\begin{aligned}\implies \displaystyle -\int e^{-2x}\cos(2x)\:\text{d}x & =\dfrac{1}{2}e^{-2x}\cos(2x)- \int \dfrac{1}{2}e^{-2x} \cdot -2 \sin(2x)\:\text{d}x\\\\& =\dfrac{1}{2}e^{-2x}\cos(2x)+ \int e^{-2x} \sin(2x)\:\text{d}x\end{aligned}$

Therefore:

$\implies \displaystyle -\int e^{-2x}\sin(2x)\:\text{d}x =\dfrac{1}{2}e^{-2x}\sin (2x) +\dfrac{1}{2}e^{-2x}\cos(2x)+ \int e^{-2x} \sin(2x)\:\text{d}x$

$\textsf{Subtract }\: \displaystyle \int e^{-2x}\sin(2x)\:\text{d}x \quad \textsf{from both sides and add the constant C}:$

$\implies \displaystyle -2\int e^{-2x}\sin(2x)\:\text{d}x =\dfrac{1}{2}e^{-2x}\sin (2x) +\dfrac{1}{2}e^{-2x}\cos(2x)+\text{C}$

Divide both sides by 2:

$\implies \displaystyle -\int e^{-2x}\sin(2x)\:\text{d}x =\dfrac{1}{4}e^{-2x}\sin (2x) +\dfrac{1}{4}e^{-2x}\cos(2x)+\text{C}$

Rewrite in the same format as the given integral:

$\displaystyle \implies - \int \dfrac{\sin(2x)}{e^{2x}}\: \text{d}x=\dfrac{\sin(2x)}{4e^{2x}}+\dfrac{\cos(2x)}{4e^{2x}}+\text{C}$

5 0

2 years ago

Multiple choices answer and explain the solution?

Oksi-84 [34.3K]

Answer:

associative property of multiplication

Step-by-step explanation:

You cant rlly explain, you just have to know your properties

7 0

3 years ago

A picture frame is shaped like a rectangle whose perimeter is 196 cm. The length is 6 times long as the width

lbvjy [14]

L=length W=width
perimeter=2Lx2W
196=2L+2W

Length can be written as 6W because it is 6 times the width. We then substitute this in so all the terms are the same

196=2(6W)+2W
196=12W+2W
196=14W
W=14cm
L= (14x6) 84cm

3 0

3 years ago