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Komok [63]
3 years ago
13

Please help. If you could/want please explain how you got it you don’t have to though no pressure

Mathematics
1 answer:
Stolb23 [73]3 years ago
4 0

Answer:

x = 5.14

Step-by-step explanation:

Both angles are equal so

5x-6 = 11x-42

42-6 = 11x - 5x

36 = 7x

x = 5.14

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Since 1 yard is 3 feet 38 feet is 38/3 yards which is 12 and 2/3 yards
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Answer:

136

Step-by-step explanation:

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the half life of c14 is 5730 years. Suppose that wood found at an archeological excavation site contains about 35% as much C14 a
Furkat [3]

Answer:

The wood was cut approximately 8679 years ago.

Step-by-step explanation:

At first we assume that examination occured in 2020. The decay of radioactive isotopes are represented by the following ordinary differential equation:

\frac{dm}{dt} = -\frac{m}{\tau} (Eq. 1)

Where:

\frac{dm}{dt} - First derivative of mass in time, measured in miligrams per year.

\tau - Time constant, measured in years.

m - Mass of the radioactive isotope, measured in miligrams.

Now we obtain the solution of this differential equation:

\int {\frac{dm}{m} } = -\frac{1}{\tau}\int dt

\ln m = -\frac{1}{\tau} + C

m(t) = m_{o}\cdot e^{-\frac{t}{\tau} } (Eq. 2)

Where:

m_{o} - Initial mass of isotope, measured in miligrams.

t - Time, measured in years.

And time is cleared within the equation:

t = -\tau \cdot \ln \left[\frac{m(t)}{m_{o}} \right]

Then, time constant can be found as a function of half-life:

\tau = \frac{t_{1/2}}{\ln 2} (Eq. 3)

If we know that t_{1/2} = 5730\,yr and \frac{m(t)}{m_{o}} = 0.35, then:

\tau = \frac{5730\,yr}{\ln 2}

\tau \approx 8266.643\,yr

t = -(8266.643\,yr)\cdot \ln 0.35

t \approx 8678.505\,yr

The wood was cut approximately 8679 years ago.

5 0
3 years ago
teacher has 27 students in her class she asked the students to form as many groups of 4 as possible how many students are not be
stepan [7]
If there are 27 students in the class and they have to form as many groups of 4 as possible, you can calculate this using the following step: 

27 / 4 = 6.75 = 6 3/4

Result: 27 students can form 6 groups of 4 students and 3 students have to form their own group.
4 0
2 years ago
3/15 as a fraction to a percent by first reducing to the lowest term
Lilit [14]
3/15 reduces to 1/5
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5 0
3 years ago
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