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laila [671]
2 years ago
11

What is the slope of the line that passes through the points (9, 1) and (10, -1)? Write your answer in simplest form.​

Mathematics
1 answer:
Otrada [13]2 years ago
7 0

We conclude that the slope of the linear equation that passes through the points (9, 1) and (10, -1) is -2.

<h3>How to get the slope of the line that passes through the points (9, 1) and (10, - 1)?</h3>

A linear equation has the general form:

y = a*x + b

Where a is the slope of the line, and b is the y-intercept.

There is a simple equation to get the slope of a point if we know two points. For a line that passes through ( a, b) and (c, d), the equation for the slope is:

a = (d - b)/(c - a)

In this case we know that our line passes through (9, 1) and (10, -1), then using the above equation, we can see that the slope is:

a = (-1 - 1)/(10 - 9) = -2

We conclude that the slope of the linear equation that passes through the points (9, 1) and (10, -1) is -2.

If you want to learn more about linear equations:

brainly.com/question/1884491

#SPJ1

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Find the coordinates of the vertices of the figure formed by each system of inequalities. x + y &lt; 9 x - 2y &lt; 12 y &lt; 2x
Vladimir [108]

Answer:

b. (10, -1), (-6, -9), (2, 7)

Step-by-step explanation:

One way to solve this problem is by graphing (see attachment). In fact, that actually is the easiest way to do this.

First, graph x + y < 9 (red part on the attachment). To do this, isolate the y so that it's like a regular linear equation: y < -x + 9. Graph the line y = -x + 9 first, and then choose a point either on the left or right of the line to plug in for x and y.

Let's just choose (0, 0), which is on the left of the line: 0 < -0 + 9  ⇒  0 < 9. Since this is a true statement, we know that we should shade the left side of the equation, and not the right side.

Now, graph x - 2y < 12 (blue part on the attachment). It's the same process here as the first inequality. For this one, we find that we also shade to the "left" of the line (it's more "up" than "left", but you get the idea).

Finally, graph y < 2x + 3 (green part on the attachment). Again, it's the same process. For this, we shade to the right.

Now look at the three points that they intersect at: they are (2, 7), (-6, -9), and (10, -1). The answer is thus B.

7 0
3 years ago
Read 2 more answers
What is the slope of a line that is perpendicular to the line whose equation is 7x−3y=107x−3y=10?
Verdich [7]
This is the concept of algebra, to get the slope of the line we need to rewrite the equation in slope intercept form y=mx+c, where m=slope, c=y-intercept.
Therefore re-writing our expression in slope-intercept form we get:
7x-3y=10
-3y=-7x+10
y=7/3x-10/3
The slope=7/3
hence we conclude that the slope of the line perpendicular to this is -3/7


4 0
3 years ago
Help this is due today!!!
kompoz [17]

Answer:

Hello!!

What is the value of m?

0.61m-1.51m=9

m=-10

Step-by-step explanation:

Isolate the variable by dividing each side by factors that do not contain the variable

Hope this helps!!

6 0
2 years ago
Read 2 more answers
Is 5/8 more than 2/3
Andre45 [30]
No. 2/3 is bigger than 5/8 because if you convert them to where the denominator is the same, 5/8= 15/24 and 2/3 is equal to 16/24
8 0
4 years ago
I’m Really lost if I could get a answer it would be greatly appreciated
Nataly [62]
<h3>Answers:</h3>

f(g(x)) = \sqrt{x^2+5}+5\\\\g(f(x)) = x+30+10\sqrt{x-1}

================================================

Work Shown:

Part 1

f(x) = \sqrt{x-1}+5\\\\f(g(x)) = \sqrt{g(x)-1}+5\\\\f(g(x)) = \sqrt{x^2+6-1}+5\\\\f(g(x)) = \sqrt{x^2+5}+5\\\\

Notice how I replaced every x with g(x) in step 2. Then I plugged in g(x) = x^2+6 and simplified.

------------------

Part 2

g(x) = x^2+6\\\\g(f(x)) = \left(f(x)\right)^2+6\\\\g(f(x)) = \left(\sqrt{x-1}+5\right)^2+6\\\\g(f(x)) = \left(\sqrt{x-1}\right)^2+2*5*\sqrt{x-1}+\left(5\right)^2+6\\\\g(f(x)) = x-1+10\sqrt{x-1}+25+6\\\\g(f(x)) = x+30+10\sqrt{x-1}\\\\

In step 4, I used the rule (a+b)^2 = a^2+2ab+b^2

In this case, a = sqrt(x-1) and b = 5.

You could also use the box method as a visual way to expand out \left(\sqrt{x-1}+5\right)^2

6 0
3 years ago
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