In your problems that ask the position of the ant labeled as B if they are crawling in a straight wire which shall call the x axis form a to b to c to d the answer to you problem base on my calculation and by understanding the best answer would be 59cm
Answer:
m<N = 32°
m(NQ) = 106°
Step-by-step explanation:
Inscribed angle = ½ of the measure of the intercepted arc (inscribed angle theorem)
<N is an inscribed angle
It's intercepted arc = arc MP = 64°
Therefore,
m<N = ½(64°)
m<N = 32°
m<P = ½(m(NQ)) (inscribed angle theorem)
53° = ½(m(NQ))
Multiply both sides by 2
2*53° = m(NQ)
106° = m(NQ)
m(NQ) = 106°
Answer:
Answer:
A. Esmeralda converted the mixed number to the wrong improper fraction.
D. Esmeralda did not divide –24 by 6 correctly.
E. Esmeralda did not use the reciprocal of the divisor.
Answer:
S = {0,2,3,4}
P(X=0) = 0.573 , P(X=2) = 0.401 , P(x=3) = 0.025, P(X=4) = 0.001
Mean = 0.879
Standard Deviation = 1.033
Step-by-step explanation:
Let the number of people having same birth month be = x
The number of ways of distributing the birthdays of the 4 men = (12*12*12*12)
The number of ways of distributing their birthdays = 12⁴
The sample space, S = { 0,2,3,4} (since 1 person cannot share birthday with himself)
P(X = 0) = 
P(X=0) = 0.573
P(X=2) = P(2 months are common) P(1 month is common, 1 month is not common)
P(X=2) = 
P(X=2) = 0.401
P(X=3) = 
P(x=3) = 0.025
P(X=4) = 
P(X=4) = 0.001
Mean, 
Standard deviation, ![SD = \sqrt{\sum x^{2} P(x) - \mu^{2}} \\SD =\sqrt{ [ (0^{2} * 0.573) + (2^{2} * 0.401) + (3^{2} * 0.025) + (4^{2} * 0.001)] - 0.879^{2}}](https://tex.z-dn.net/?f=SD%20%3D%20%5Csqrt%7B%5Csum%20x%5E%7B2%7D%20P%28x%29%20-%20%5Cmu%5E%7B2%7D%7D%20%20%5C%5CSD%20%3D%5Csqrt%7B%20%5B%20%280%5E%7B2%7D%20%2A%200.573%29%20%2B%20%282%5E%7B2%7D%20%20%2A%200.401%29%20%2B%20%283%5E%7B2%7D%20%2A%200.025%29%20%2B%20%284%5E%7B2%7D%20%2A%200.001%29%5D%20-%200.879%5E%7B2%7D%7D)
SD = 1.033
1824 the estimate is 1820
