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1 year ago

15

V=2/3 ayuda porfavooooor

1 answer:

GalinKa [24]1 year ago

3 0

Answer: answer is a

Step-by-step explanation:

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Samuel is looking at the floor plan of his house to determine how much carpet he needs to buy for his basement. Based on the flo

DerKrebs [107]

Answer:

B) First, find two areas using (4m x 10m = 40m2) and (8m x 3m = 24m2). Next, add (40m2 + 24m2 = 64m2).

Step-by-step explanation:

Samuel should is looking to find the area of his basement in order to cover it with carpet.

An area is calculated by multiplying two dimensions (so answers A and D are not it).

Best solution is to divide the area into two large rectangles then ADD them together to get the total area.

The only scenario where he could have subtracted something based on his plan is if he would have multiplied the 10m by the 12m then subtracted the area that is not part of his basement (7mx8m). He would have achieved the same result of course, but by going a different way.

3 0

3 years ago

A)Agudos<br> B)suplementares <br> C)congruentes<br> D)complementares <br> E)Rasos

True [87]

Answer:

The correct answer to this question is complementars

8 0

3 years ago

Can someone help me this is really confusing????? What is the solution set for the open sentence with the given replacement set?

IgorLugansk [536]

The answer is:

3

w^2 - 1 = w + 5

3^2 - 1 = w + 5

3^2 = 3(3) = 9

9-1 = 8

8 = 3 + 5

8 = 8

6 0

3 years ago

Let A and B be events with =PA0.7, =PB0.3, and =PA or B0.9. (a) Compute PA and B. (b) Are A and B mutually exclusive? Explain. (

kvasek [131]

Answer:

a) $P(A \cup B) = P(A) +P(B) - P(A\cap B)$

And if we solve for $P(A \cap B)$ we got:

$P(A \cap B) = P(A) + P(B) -P(A\cup B)= 0.7+0.3-0.9 = 0.1$

b) False

The reason is because we don't satisfy the following relationship:

$P(A\cup B) = P(A) + P(B)$

We have that:

$0.9 \neq 0.3+0.7 =1$

c) False

In order to satisfy independence we need to have the following condition:

$P(A \cap B) = P(A) *P(B)$

And for this case we don't satisfy this relation since:

$0.1 \neq 0.7*0.3 = 0.21$

Step-by-step explanation:

For this case we have the following probabilities given:

$P(A) = 0.7, P(B) =0.7, P(A \cup B) =0.9$

Part a

We want to calculate the following probability: $P(A \cap B)$

And we can use the total probability rule given by:

$P(A \cup B) = P(A) +P(B) - P(A\cap B)$

And if we solve for $P(A \cap B)$ we got:

$P(A \cap B) = P(A) + P(B) -P(A\cup B)= 0.7+0.3-0.9 = 0.1$

Part b

False

The reason is because we don't satisfy the following relationship:

$P(A\cup B) = P(A) + P(B)$

We have that:

$0.9 \neq 0.3+0.7 =1$

Part c

False

In order to satisfy independence we need to have the following condition:

$P(A \cap B) = P(A) *P(B)$

And for this case we don't satisfy this relation since:

$0.1 \neq 0.7*0.3 = 0.21$

4 0

3 years ago

torisob [31]

The computation shows that the number of possible ways will be 12.

<h3>How to calculate the value?</h3>

From the information given, Mary has four t-shirts-T₁, T2, T3, and T4, and three pairs of jeans-J1, J2, and J3.

Therefore, the number of possible ways that she can choose her outfit will be:

= 4 × 3 = 12

In conclusion, the correct option is 12.

Learn more about computations on:

brainly.com/question/4658834

#SPJ1

5 0

2 years ago