The proof of DE is parallel to BC in the given triangle is shown.
<h3>What is defined as the parallel line?</h3>
- Parallel lines are defined as two lines that remain the same distance away and never intersect.
- To be parallel, two lines must be driven in the same plane, which is a perfectly flat surface such as a wall or sheet of paper.
As per the given data in the question;
A, B and C are the vertices of a triangle.
- A has coordinates (4, 6)
- B has coordinates (2,-2)
- C has coordinates (-2,-4)
Whereas,
D lies at the midpoint of AB.
E lies at the midpoint of AC.
The mid piont formula is;
Mid point = (x₁ + x₂ / 2, y₁ + y₂ / 2)
The coordinates of D is found by the mid point formula of coordinates.
Put the coordinates of A (4, 6) and B (2,-2).
D = (4 + 2 / 2, 6 - 2 / 2)
D = (3, 2)
The coordinates of E is found by the mid point formula of coordinates.
Put the coordinates of A (4, 6) and C (-2,-4)
E = (4 - 2 / 2, 6 - 4 / 2)
E = (1, 1)
Now, the slope is calculated by;
m of DE = (y₂ - y₁)/(x₂ - x₁)
The slope of E is
m of DE = (1 - 2)/(1 - 3) = 1/3
Slope of BC
M of BC = (-4 + 2)/(-4 - 2)
M of BC = 1/2
As, the slope of both line DE and BC are equal. Thus, both line are parallel to each other.
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