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Temka [501]
9 months ago
14

An appliance manufacturer wants to contract with a repair shop to handle authorized repairs in Indianapolis. The company has set

an
acceptable range of repair time of 50 minutes to 90 minutes. Two firms have submitted bids for the work. In test trials, one firm had a
mean repair time of 74 minutes with a standard deviation of 4.0 minutes and the other firm had a mean repair time of 72 minutes with a
standard deviation of 5.1 minutes. (Do not round intermediate calculations. Round your answers to 2 decimal places.)

Firm Cpk

1 ___
2 ___

Which firm would you choose?

Firm 1
Firm 2
None
Mathematics
1 answer:
jeyben [28]9 months ago
8 0

The best firm for the Appliance manufacturer for the repair work is Firm 2 .

In the question ,

it is given that ,

An appliance manufacturer wants to contract with a repair shop to handle authorized repairs in Indianapolis .

The acceptable range of the repair time is 50 minutes to 90 minutes.

the mean repair time for firm 1 = 74 minutes and standard deviation of 4 minutes .

the mean repair time for firm 2 = 72 minutes and standard deviation of 5.1 minutes .

the range is calculated using the formula

Range = Mean ± Standard Deviation

So , for firm 1 ,

the Range = 74 ± 4

= 74 + 4       and      74 - 4

= 78     and   70

the range for firm 2 is

= 72 ± 5.1

= 72 + 5.1      and      72 - 5.1

= 7.1        and       66.9  

The second company has a lower range and it should be preferred .

Therefore ,  The best firm for the Appliance manufacturer for the repair work is Firm 2 .

Learn more about Standard Deviation here

brainly.com/question/23611887

#SPJ1

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Which of the following is a factor of x2 − 8x + 15?
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Answer:

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Step-by-step explanation:

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Find the product. Simplify your answer.<br> -5 • 9t<br> 7s 7
Sauron [17]

Answer:

-13            

 ——— = -0.20635  

 63            

Step-by-step explanation:

Step  1  :

           7

Simplify   —

           9

Equation at the end of step  1  :

 4    7

 — -  —

 7    9

Step  2  :

           4

Simplify   —

           7

Equation at the end of step  2  :

 4    7

 — -  —

 7    9

Step  3  :

Calculating the Least Common Multiple :

3.1    Find the Least Common Multiple

     The left denominator is :       7  

     The right denominator is :       9  

       Number of times each prime factor

       appears in the factorization of:

Prime  

Factor   Left  

Denominator   Right  

Denominator   L.C.M = Max  

{Left,Right}  

7 1 0 1

3 0 2 2

Product of all  

Prime Factors  7 9 63

     Least Common Multiple:

     63  

Calculating Multipliers :

3.2    Calculate multipliers for the two fractions

   Denote the Least Common Multiple by  L.C.M  

   Denote the Left Multiplier by  Left_M  

   Denote the Right Multiplier by  Right_M  

   Denote the Left Deniminator by  L_Deno  

   Denote the Right Multiplier by  R_Deno  

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Making Equivalent Fractions :

3.3      Rewrite the two fractions into equivalent fractions

Two fractions are called equivalent if they have the same numeric value.

For example :  1/2   and  2/4  are equivalent,  y/(y+1)2   and  (y2+y)/(y+1)3  are equivalent as well.

To calculate equivalent fraction , multiply the Numerator of each fraction, by its respective Multiplier.

  L. Mult. • L. Num.      4 • 9

  ——————————————————  =   —————

        L.C.M              63  

  R. Mult. • R. Num.      7 • 7

  ——————————————————  =   —————

        L.C.M              63  

Adding fractions that have a common denominator :

3.4       Adding up the two equivalent fractions

Add the two equivalent fractions which now have a common denominator

Combine the numerators together, put the sum or difference over the common denominator then reduce to lowest terms if possible:

4 • 9 - (7 • 7)     -13

———————————————  =  ———

      63            63  

Final result :

 -13            

 ——— = -0.20635  

 63            

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