<span>Point B has coordinates (3,-4) and lies on the circle. Draw the perpendiculars from point B to the x-axis and y-axis. Denote the points of intersection with x-axis A and with y-axis C. Consider the right triangle ABO (O is the origin), by tha conditions data: AB=4 and AO=3, then by Pythagorean theorem:
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{Note, that BO is a radius of circle and it wasn't necessarily to use Pythagorean theorem to find BO}
<span>The sine of the angle BOA is</span>

Since point B is placed in the IV quadrant, the sine of the angle that is <span> drawn in a standard position with its terminal ray will be </span>
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Answer:
The second one
Step-by-step explanation:
Its not the third one because it is an equilateral
its not the first one because it is not obtuse
The triangle is isosceles
obtuse means the angles are big
the angles are small so they are acute
I hope this helps you
Answer:
29t + 24
Step-by-step explanation:
5(5t + 6) + 2(2t - 3)
Open Parentheses first.
5* 5t = 25t
5 * 6 = 30
25t + 30 + 2(2t - 3)
Open others
2 * 2t = 4t
2 * 3 = 6
25t + 30 + 4t - 6
Match like terms
29t + 24
Answer:
Step-by-step explanation:
take angle C as reference angle
using cos rule
cos C=adjacent/hypotenuse
cos C=21/75
cos C=0.28
C=
0.28
C=73.7 degree
Okay so instead of dividing you will cross multiply.
4n(15)=84(5)
60n=420
420/60=7
Answer: n=7