1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
sukhopar [10]
1 year ago
12

Find the average rate of change over the given interval: f(x) = 3x, [1, 4]

Mathematics
2 answers:
lara31 [8.8K]1 year ago
8 0
What subject is This
victus00 [196]1 year ago
8 0

Answer:

26

Step-by-step explanation:

I got it right on imagine math

You might be interested in
56 * 65 to the 8th power in scientific notation and result
Ber [7]
The answer is 17, 844, 109, 521, 875, 000.

in scientific notation its 1.7844109521875 * 10 to the 16th power
7 0
3 years ago
Read 2 more answers
What is 25% of 300? *
Rina8888 [55]

Answer:

75

Step-by-step explanation:

OF means multiplication!

25 as a decimal is

0.25 x 300 =

75

8 0
3 years ago
A $30 pair of pants is on sale for 15% off. How
ExtremeBDS [4]

Answer:

$25.50

Step-by-step explanation:

15 percent off-> 85 percent is not off

therefore 0.85*30 is how you find the percent off

0.85*30=25.5

Hello again :). and of course I shall help you with any questions you may have while I'm here my friend

6 0
3 years ago
Read 2 more answers
Prove or give a counterexample:
ozzi

Answer:

See proof below.

Step-by-step explanation:

True

For this case we need to use the following theorem "If v_1, v_2,....v_k are eigenvectors of an nxn matrix A and the associated eigenvalues \lambda_1, \lambda_2,...,\lambda_k are distinct, then v_i's are linearly independent". Now we can proof the statement like this:

Proof

Let A a nxn matrix and we can assume that A has n distinct real eingenvalues let's say \lambda_1, \lambda_2, ....,\lambda_n

From definition of eigenvector for each one \lambda_i needs to have associated an eigenvector v_i for 1 \leq i \leq n

And using the theorem from before , the n eigenvectors v_1,....,v_n are linearly independent since the \lambda_i 1\leq i \leq n are distinct so then we ensure that A is diagonalizable.

4 0
3 years ago
~~~ 20 POINTS ~~~
Ilia_Sergeevich [38]
A) Lets write our equations.

22x + 100 = 25x + 70

Now lets solve step-by-step.

Apply the inverse operation            22x + 100 = 25x + 70
                                                       -22x             -22x

25x - 22x = 3x

3x + 70 = 100
       -70     - 70               We subtract 70 from both sides because (inverse                                                                                                                  operation)

3x = 30

3x/3 = 30/3
x = 30/3
x= 10

B) We need to find which one is the most cheap.

Lets pick an integer to replace x.

22x + 100 = 25x + 70

Lets choose '2'

22(2) + 100 = 25(2) + 70
44 + 100
 50 + 70

144
120

The first one : Country Carpets charges $144 , while at the same rate, City carpets charges 120.

So, obviously, City Carpets is cheaper than that other one, so he would most likely choose that one.  
5 0
4 years ago
Read 2 more answers
Other questions:
  • Convert 1 over 8 to a fraction
    7·2 answers
  • What is 240 divided by six
    12·1 answer
  • What is 1.16 rounded to the nearest tenths?
    5·2 answers
  • Given f(x) = 3x + 2 and g(x) = 2x² , find the following composite functions:
    6·1 answer
  • For the following system, use the second equation to make a substitution for y in the first equation. 3x + y = 1 y + 4 = 5x What
    12·1 answer
  • If you have 30 respondents identifying their political preference (i.s., Democrat, Republican, or independent), what would the e
    8·1 answer
  • Pls solve plsssssssss
    6·1 answer
  • I’ll give brainliest
    13·2 answers
  • HELP ASAP PLSPLSPLSPLSPLSPLSPLSPLSPLSPLSPLSPLSPLSPLS
    12·2 answers
  • 7 L of an acid solution was mixed with 3 L of a 15% acid solution to make a 29% acid solution. What is the percent concentration
    7·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!