The quantity of each type of seats sold are as follows:
- Movie and a dinner seat = 200
According to the question,there are four times as many 3D, x seats as Dinner and a Movie, y seats.
That is, x = 4y
Also, total seats
= (x) + (y) + (z) = 3000...….............eqn(1)
Also, If the theater brings in $53,000 when tickets to all 3000 seats are sold.
- 20x + 35y + 15z = 53000...........eqn(2)
By substituting 4y for x in equations 1 and 2; we have;
<em>5y + z = 3000</em>..…........eqn(3) and
<em>115y + 15z = 53000</em>.........eqn(4)
By solving equations 3 and 4 simultaneously; we have;
y = 200 and z = 2000
and since x = 4y
x = 800
The quantity of each type of seats sold is as follows:
- Movie and a dinner seat = 200
Read more:
brainly.com/question/12413726
Answer:
MOP=33
Step-by-step explanation:
MOP + MON = NOP
Substitute what we know
MOP = 3x-3
MON = 4x+9
NOP = 90 right angle
3x-3+4x+9 = 90
Combine like terms
7x+6 =90
Subtract 6 from each side
7x+6-6=90-6
7x = 84
Divide each side by 7
7x/7 = 84/7
x =12
We need to find MOP
MOP = 3x-3
=3(12)-3
36-3
33
your answer is c 29. To figure this out take 59-180= 121. Then add 121 and 30 =151. next subtract 151 from 180 and you get C 29
The mid point of DE is (3,-1)
This can be found with Pythagorean Theorem
The length of “a” is 6. The length of “b” is 4.
The length of DE is ≈ 7.21. The midpoint of this value is found at coordinates (3,-1)
