The probability of the player missing a shot at least once is 1.00 - 0.70 = 0.3.
Therefore the average number of missed double goals in 2500 trials is given by:
The difference between the largest and biggest amount is 7.
C= 3b + 2d
Subtract 3b first.
C-3b = 2d
Divide by 2.
C-3b/2 = d
OR
C-3b
-------- = d Your final answer!
2