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jeka94
1 year ago
7

Please do #4 It’s it the one on the bottom

Mathematics
1 answer:
spin [16.1K]1 year ago
3 0

We need to graph this equation:

16x+2y=300

Its solutions are the points through which it graph passes. Since it's a linear equation its graph is a straight line and we only need two of its points to draw it. But before graphing let's re-write the equation. We can substract 16x from both sides:

\begin{gathered} 16x+2y=300 \\ 16x+2y-16x=300-16x \\ 2y=300-16x \end{gathered}

And we divide both sides by 2:

\begin{gathered} \frac{2y}{2}=\frac{300-16x}{2}=\frac{300}{2}-\frac{16x}{2} \\ y=150-8x \end{gathered}

So now with this equation if we pick two random x values we'll get their corresponding y values. This way we'll find two points that are part of the graph which is the line that passes through both. We can begin with x=0:

y=150-8\cdot0=150

So the first point is (0,150). Then we can take x=10 and we get:

y=150-8\cdot10=150-80=70

So the second point is (10,70). Then the graph is the line that passes through points (0,150) and (10,70). In order to represent it

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3 years ago
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Which is the value of this expression when a=-2 and b=-3
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Answer:

\frac{729}{64}

Step-by-step explanation:

The given expression is

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When we say "evaluate the expression" refers to replacing the given values in the expression. Then, we solve each power in the numerator and denominator. After that, we solve each product in the fraction. At the end, we apply the square power. As follows

(\frac{3a^{-3}b^{2}  }{2a^{-1} b^{0} } )^{2}=(\frac{3(-2)^{-3}(-3)^{2}  }{2(-2)^{-1} (-3)^{0} } )^{2}=(\frac{3(\frac{1}{-8})(9)}{2(\frac{1}{-2} (1))} )^{2} =(\frac{-\frac{27}{8} }{-1} )^{2} =\frac{27^{2} }{8^{2} } =\frac{729}{64}

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3 years ago
Sam bought 2 shirts. Deal A shirt was $20 and was on
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Deal A was the better deal.

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22*.16= 3.52 dollar discount for a total of 22-3.52 =$18.48

Even though deal B had the larger discount you will still be paying a bit more compared to deal A

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