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3 years ago

How many hours would someone earns 7.50 per hour have to work to earn $116.25

Mathematics

1 answer:

SCORPION-xisa [38]3 years ago

5 0

Let h = amount of hours

$7.5h=116.25$

Since they earn $7.50 per hour, we can multiply that by an unknown amount of hours to get $116.25. Let's solve:

$7.5h=116.25$

Divide both sides by 7.5 to isolate the h, amount of hours.

$\frac{7.5h}{7.5}=\frac{116.25}{7.5}$

Simplify.

$h=15.5$

In conclusion, someone would have to work 15.5 hours to earn $116.25 if they earn $7.50 per hour.

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3 years ago

The length of a rectangle is 7 more than the width the area is 744 square centimeters find length and width of rectangle

andrezito [222]

Answer:

$l=31\ cm\\\\w=24\ cm$

Step-by-step explanation:

The formula that is used to calculate the area of a rectangle is:

$A=lw$

Where "l" is the lenght and "w" is the width.

You know that the area of that rectangle is:

$A=744\ cm^2$

And, according to the exercise, its lenght is 7 more than its width; then:

$l=w+7$

Then, you can make the corresponding substitution into the formula $A=lw$ :

$744=(w+7)w$

Simplify:

$744=w^2+7w\\\\w^2+7w-744=0$

Factor the equation. Find two numbers whose sum is 7 and whose product is -744. These are 31 and -24.

Then, you get:

$(w-24)(w+31)=0\\\\w_1=24\\\\w_2=-31$

The width of the rectangle is the positive value:

$w=24\ cm$

Then, the lenght is:

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8 0

3 years ago

For each pair figures, find the ratio of the area of the first figure to the area of the second. 14mm 7mm

Paraphin [41]

The ratio of the area of the first figure to the area of the second figure is 4:1

<h3>Ratio of the areas of similar figures </h3>

From the question, we are to determine the ratio of the area of the first figure to the area of the second figure

The two figures are similar

From one of the theorems for similar polygons, we have that

If the scale factor of the sides of two similar polygons is m/n then the ratio of the areas is (m/n)²

Let the base length of the first figure be ,m = 14 mm

and the base length of the second figure be, n = 7 mm

∴ The ratio of their areas will be

$(\frac{14 \ mm}{7 \ mm})^{2}$

$= \frac{196 \ mm^{2} }{49\ mm^{2} }$

$=\frac{4}{1}$

= 4:1

Hence, the ratio of the area of the first figure to the area of the second figure is 4:1

Learn more on Ratio of the areas of similar figures here: brainly.com/question/11920446

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2 years ago

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3 years ago

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What is one of the solutions to the following system of equations?

Amanda [17]

Answer:

(8,-1)

Step-by-step explanation:

Given : $x^{2} +y^{2} =65$

$x+y=7$

To Find: solution of given system of equations.

Solution:

Equation a : $x^{2} +y^{2} =65$

Equation b : $x+y=7$

Substitute the value of y from equation b in equation a

y from equation b : y = 7-x

Now substitute value of y in equation a

Thus equation a becomes:

$x^{2} +(7-x)^{2} =65$

$x^{2} +49+x^{2}-14x =65$

$2x^{2} -14x =65-49$

$x^{2} -7x -8=0$

$x^{2} -8x+x -8=0$

$x(x-8)+1(x-8)=0$

$(x+1)(x-8)=0$

⇒ x= -1 and x = 8

Now substitute values of x in equation b to obtains values of y

⇒ $x+y=7$

for x = -1

⇒ $-1+y=7$

⇒ $y=7+1$

⇒ $y=8$

Thus (x,y)=(-1,8)

For x =8

⇒ $8+y=7$

⇒ $y=7-8$

⇒ $y=-1$

Thus (x,y)=(8,-1)

Hence Option A is the correct solution .

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4 years ago

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