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Mila [183]
3 years ago
8

Two competing gyms each Two competing gyms each offer childcare while parents work out. Gym A charges $9.00 per hour of childcar

e. Gym B charges $0.75 per 5 minutes of childcare. Which comparison of the childcare costs is accurate? Gym B charges $1.05 less per hour than Gym A. Gym B charges $1.50 less per hour than Gym A. Gym B charges $5.25 less per hour than Gym A. Gym B and Gym A charge the same hourly rate for childcare. offer childcare while parents work out. Gym A charges $9.00 per hour of childcare. Gym B charges $0.75 per 5 minutes of childcare. Which comparison of the childcare costs is accurate? Gym B charges $1.05 less per hour than Gym A. Gym B charges $1.50 less per hour than Gym A. Gym B charges $5.25 less per hour than Gym A. Gym B and Gym A charge the same hourly rate for childcare.
Mathematics
2 answers:
jek_recluse [69]3 years ago
6 0

Answer:

Gym B and Gym A charge the same hourly rate for childcare.

Step-by-step explanation:

Gym A charges $9.00 per hour of childcare.

Gym B charges $0.75 per 5 minutes of childcare.

Do, gym B charges \frac{0.75}{5}\times60= 9 dollars per hour.

We can see that both gyms have the same hourly rate that is $9.

So, the correct answer is :

Gym B and Gym A charge the same hourly rate for childcare.

STatiana [176]3 years ago
4 0
Gym A charges 9 per hr

Gym B charges 0.75 per 5 minutes....0.75/5 = 0.15 per minute...60 minutes in an hr.....60 * 0.15 = 9 per hr

so Gym A and Gym B charge the same hourly rate
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NEED QUESTION ASAP<br><br><br> Help please
agasfer [191]

Answer:

(x-3)(x-2)

Step-by-step explanation:

x^2-5x+6

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5 0
2 years ago
Can I please have some help !
maw [93]

Answer:

No because when you set it up it would be 11/9.4 which equals 1.17

Then you do the other side, 10/8.4 which equals 1.19

And 1.17 doesn't equal 1.19 so they are not similar


7 0
3 years ago
The percent of concentration of a certain drug in the bloodstream x hours after the drug is administered is given by K(x) 5x/x^2
Olegator [25]

Given :

The percent of concentration of a certain drug in the bloodstream x hours after the drug is administered is given by K(x) = \dfrac{5x}{x^2+9}.

To Find :

Find the time at which the concentration is a maximum. b. Find the maximum concentration.

Solution :

For maximum value of x, K'(x) = 0.

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Therefore, maximum value drug in bloodstream is 5/6 at time x = 3 units.

Hence, this is the required solution.

5 0
3 years ago
You want to solve 11% of what number is 22. Explain how you can solve that by using a proportion
Doss [256]
Write the first ratio as 11/100 and set it equal to 22/n.

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*Check*: 11% of 200=22
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