Frederick tossed a number cube and then tossed a coin 100 times as part of an experiment. He recorded the number of times he tos
sed a six or tossed a number other than six, and the number of times the coin landed on heads or tails. The results are listed in the table below.
Based on these results, what was the probability that Frederick’s coin landed on tails after he tossed a six?
A.3/25
B. 31/100
C. 12/31
D. 69/100
Based on these results, what was the probability that Frederick’s coin landed on tails after he tossed a six?
A.3/25
B. 31/100
C. 12/31
D. 69/100
2 answers:
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<u>Testing the hypothesis</u>, it is found that since the <u>p-value of the test is 0.0042 < 0.01</u>, it can be concluded that the proportion of subjects who respond in favor is different of 0.5.
At the null hypothesis, it is tested if the <u>proportion is of 0.5</u>, that is:
At the alternative hypothesis, it is tested if the <u>proportion is different of 0.5</u>, that is:
The test statistic is given by:
In which:
is the sample proportion.
- p is the value tested at the null hypothesis.
- n is the sample size.
In this problem, the parameters are given by:
The value of the test statistic is:
Since we have a <u>two-tailed test</u>(test if the proportion is different of a value), the p-value of the test is P(|z| > 2.86), which is 2 multiplied by the p-value of z = -2.86.
Looking at the z-table, z = -2.86 has a p-value of 0.0021.
2(0.0021) = 0.0042
Since the <u>p-value of the test is 0.0042 < 0.01</u>, it can be concluded that the proportion of subjects who respond in favor is different of 0.5.
A similar problem is given at brainly.com/question/24330815