Let f: 4 → and c(t): → 4. suppose ∇f(1, 1, π, e6) = (0, 1, 2, −4), c(π) = (1, 1, π, e6), and c'(π) = (13, 12, 0, 1). find d(f ∘
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Answer:
Mass of the cat = 16800kg
Step-by-step explanation:
The volume of the box = its length * its breath * its height- 4m × 3m × 2m = 24
The standard density of water is 1000 Kg/
By Archimedes principle, the mass of a body floating body is equivalent to the mass of the volume liquid displaced
in this case we have
Mass of water displaced = Density of the water × Volume of the water displaced = 1000 Kg/ × 24
= 24000kg
The mass of the box = Box density × Box volume = 24 × 300kg/
= 7200 kg Hence the mass of water displaced = mass of the foating box + mass of th cat
24000kg = mass of cat +7200kg
mass of cat = 24000kg - 7200kg = 16800kg