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Mariulka [41]
1 year ago
6

What is the domain, range, and function? {(-3, 3), (1, 1), (0, -2), (1,4), (5, -1)}

Mathematics
1 answer:
wolverine [178]1 year ago
8 0

The domain are all the inputs, that is; the x-values

Domain = { -3, 0, 1, 5}

The range are all the output, that is the y-values

Range = { 3, 1, -2, 4, -1}

This is just a relation and not a function, as we have more than 2 same value of x

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Answer:

(a) I attached a photo with the diagram.

(b) f(x) = \big( \frac{1}{2} \big)^{x-1}

(c) 1/4

(d) 4

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Step-by-step explanation:

(a) I attached a photo with the diagram.

(b) The easiest way to think about this part is in terms of combinatorics. Think about it like this.

To begin with, look at the three each level of the three represents a possible outcome of throwing the coin n-times. If you throw the coin 3 times at the end in total there are 8 possible outcomes. But The favorable outcomes are just 2.

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f(x) = P(X=x) = \frac{2}{2^x}  = \frac{1}{2^{x-1}} = \big( \frac{1}{2} \big)^{x-1}

(c)

P(X = 0) = 0 because it is not possible to have two consecutive tails or heads.

E(X > 4) = 1 - P(X \leq 3) = 1 - ( P(X = 0 ) + P(X = 1) + P(X = 2) + P(X = 3))\\= 1 - ( \frac{1}{2} + \frac{1}{4} ) = \frac{1}{4}

(d)

Remember that this is a geometric distribution therefore

E[X] = p/(1-p), in this case  p = 1/2 so E[X] = 1 and

E[X+1]^2 = ( E[X] +1 )^2  = (1+1)^2 = 2^2 = 4

Also

(e)

This is a geometric distribution so its variance is

Var(X) = \frac{1-p}{p^2} = 1/2 / 1/4 = 1/2

And using properties of variance

Var(kX - k ) = Var(kX) = k^2 var(X) = k^2 /2

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Answer:

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