Question

Hi, can anyone help me with this one here? Thanks.

Answer 1

Answer:

Option 4

Step-by-step explanation:

Let $f(x)=ax^2+bx+c$.

$f(0)=a(0)^2+b(0)+c=-4 \implies c=-4 \\ \\ f(-1)=a-b-4=-3 \implies a-b=1 \\ \\ f(2)=4a+2b-4=6 \implies 2a+b=5 \\ \\ \therefore (a-b)+(2a+b)=6 \implies a=2 \implies b=1 \\ \\ \therefore f(x)=2x^2+x-4$.