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balandron [24]
2 years ago
6

Find the coordinates of point P on →AB that partitions the segment into the given ratio AP to PB .

Mathematics
1 answer:
marysya [2.9K]2 years ago
6 0

The line segment AB is divided at point P, which has coordinates P(0,-7.5)

A line segment is a section of a line that connects two locations to create a straight line or we can say that is connects two distinct points together to form a single line. It is extendable to either side.

Given are,

A line segment AB with coordinates of A(0,0 ) and B(-15,0) respectively

Two minor line segments, AP and PB, are created from the line segment AB by the provided point P

We must determine the dividing point's coordinates, or P.

We'll apply the formula provided,

The coordinates of the point P are given by  = (\frac{x1+x2}{2},\frac{y1+y2}{2} )

Now, x1 = 0, x2 = 0, y1 = -15, y2 = 0

Putting values in the formula, we get

(\frac{0+0}{2}, \frac{0-15}{2})

(0,-7.5)

Hence, the point P which partitions the line segment AB have coordinates as P(0,-7.5)

To learn more about Line Segment, here

brainly.com/question/25727583

#SPJ4

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Answer:

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Step-by-step explanation:

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(\frac{x_{1}+x_{2}  }{2}, \frac{y_{1}+y_{2}  }{2} )

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The equation of a line in slope- intercept form is

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Here m = - \frac{4}{3} , then

y = - \frac{4}{3} x + c ← is the partial equation

To find c substitute the midpoint (1, 7) into the partial equation

7 = - \frac{4}{3} + c ⇒ c = \frac{21}{3} + \frac{4}{3} = \frac{25}{3}

y = - \frac{4}{3} x + \frac{25}{3} ← equation of perpendicular bisector

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